Find the standard form of the equation of each circle with the endpoints of a diameter (1,8) and (-3,2)

Factor completely

luda_lava [24]

Answer:

B)

D)

Step-by-step explanation:

1. $7x^3y+14x^2y^3-7x^2y^2$

The GCF of all the term of the above polynomial is $7x^2y$ , hence we take it outside and form a bracket

$7x^2y(x+2y^2-y)$

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

2. $5x(x+3)+6(x+3)$

The GCF of all the term of the above polynomial is $(x+3)$ , hence we take it outside and form a bracket

$(x+3)(5x+6)$

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

3. $8x^5+2x^4+4x^2$

The GCF of all the term of the above polynomial is $2x^2$ , hence we take it outside and form a bracket

$2x^2(4x^3+x^2+2)$

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (D) is the right answer

4 0

3 years ago

Please help i dont understand this at all

tamaranim1 [39]

I have no idea but I googled and I got 0.6 I hope this helps!

5 0

3 years ago

Yesterday I ran 9.6 miles at an average speed of 0.4 miles per 5 minutes. How long did it take me to run the 96 miles?

Alexeev081 [22]

Answer:

Step-by-step explanation:

This is how we do it in college, I hope I can be of some help.

First, you multiple 9.6 miles with 5 minutes. Then, you divide your answer with 0.4 miles. Next, you cancel the two mile units because of division and then be left with 120 minutes.

9.6 miles x <u> 5 minutes </u> = <u> 48 miles x minute </u> = 120 minutes

0.4 miles 0.4 miles

8 0

3 years ago

In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music,

aleksley [76]

Answer:

210

Step-by-step explanation:

Given:

Medals in sports = 40

Medals in dance = 25

Medals in music = 212

Total students that received medals = 55

Total students that received medals in all three categories = 6

Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

n(A∩B∩C)= 6

To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

= 283 - 73

= 210

Number of students that get medals in exactly two of these categories are 210

6 0

3 years ago

Find the surface area of the prism

vlabodo [156]

Answer:

The answer is 190

Step-by-step explanation:

3x5x2 30

3x10x2 60

5x10x2 100

add them together to get 190

5 0

2 years ago