I will assume that you meant:
(x+4)/(-3x^2+12x+36) factor the denominator...
(x+4)/(-3(x^2-4x-12))
To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions...
jk=ac=-12 and j+k=b=-4 so j and k must be 2 and -6 and the factors are then:
(x+2)(x-6) so we are now left with:
(x+4)/(-3(x+2)(x-6))
The only restriction on this function is that division by zero is undefined, so x cannot equal -2 or 6
Answer:
I am not sure but for
CAE it is 65˚
CBD it is 65˚
Step-by-step explanation:
x+40=3x-10
Move the 3x to the other side by subtracting by 3x on both sides
x-3x+40=3x-3x-10
The equation now looks like this:
-2x+40=-10
Move 40 to the other side by subtracting 40 both sides:
-2x+40-40=-10-40
-2x=-50
Divide by -2 on both sides:
-2x/-2=-50/-2
x=25
Since we found out what x is we can replace x in both CAE and CBD:
For CBD: 25+40 is 65
For CAE: 3(25)-10 is 65
Answer:
4 radical 5
Step-by-step explanation:
