Answer:
1 is a solution, 2 isnt
Step-by-step explanation:
For number 1,both problems are true with the given values of x and y, but with number 2, oy the second problem is true
Answer:
2.28% probability that a person selected at random will have an IQ of 110 or greater
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or greater?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.9772
1 - 0.9772 = 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or greater
Y2-y1/x2-x1
121.5-58.5/27-13
63/14
$4.5 an hour.
Answer:
75.47
Step-by-step explanation:
<em>Hey there !!!!!</em>
<em>to, see how much did the man travel in total. you just add all of the distances that the man traveled.</em>
<em>he traveled:</em>
<em>13.2 by tairn</em>
<em>45.07 by bicycle </em>
<em>17.2 by car </em>
<em>if you add all of them up :</em>
<em>45.07 + 13.2 = 58.27 </em>
<em>58.27 + 17.2 = 75.47</em>
<em>have a wonderful day </em>
Nothing changes if you don't add anything.
Example:
10+10=20
20+0=20
nothing changes.