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k0ka [10]
3 years ago
14

Can someone help me?

Mathematics
1 answer:
Assoli18 [71]3 years ago
4 0
I hope the answer is 22.5=x
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Last month you went on three hikes. One hike was 2 3/4 miles long, one was 1 1/2 miles long, and the other was 3 3/8 miles long
Tresset [83]
OK. So I hiked 7 and 5/8 miles last month. (In my dreams !). Do you have a question to ask ?
3 0
3 years ago
Forty-two is what percent of 70? <br><br> A.21%<br><br> B.60%<br><br> C.74%<br><br> D.167%
Ad libitum [116K]
60% is the answer you are seeking. 
5 0
4 years ago
The line is parallel to
tino4ka555 [31]

Recall that parallel lines have the same slope.

A line parallel to y= (-3/5)x + 8 would have the same equation EXCEPT for a different constant, C, replacing that '8.'

This new line passes thru (-5,-3).  In y= (-3/5)x + C, replace x with -5 and replace y with -3.  Then:

-3 = (-3/5)(-5) + C.  Find C:

-3 = 3 + C.  Thus, C = 6


Thus, the equation of the new line is y= -(3/5)x - 6

Check:  Let x = -5 and y = -3.  Is the above equation true?

-3 = (-3/5)(-5) - 6

-3 = 3 - 6, or -3 = -3.

8 0
3 years ago
Help wanted!! 10 points up (-:
Lena [83]
HEY THERE!!

AS we know COSINE =PERPENDICULAR /BASE

SO ACCORDING TO ABOVE IMAGE
PERPENDICULAR is 5 ft
AND BASE
is 8 ft

so now cosine A = 5/ 8

MEAN THE CIRRECT ANSWER IS (D)

HOPE IT HELPED YOU
3 0
3 years ago
a box with a square base and open top must have a volume of 70304 c m 3 cm3 . we wish to find the dimensions of the box that min
Dmitriy789 [7]

The box should have base 52 cm by 52 cm and height 26 cm.

What is volume?

A three-dimensional space's occupied volume is measured. It is frequently expressed as a numerical value using SI-derived units, other imperial units, or US customary units. Volume definition and length definition are connected.

The Volume of a box with a square base x by x cm and height h cm is

V = x^2h

Since the surface area directly affects the amount of material used, we can reduce the amount of material by reducing the surface area.

The surface area of the box described is  A = x^2 + 4xh

We need A as a function of x alone, so we'll use the fact that

V = x^2h= 70304 cm^3

⇒ h = \frac{70304}{x^2}

So, the area becomes,

A = x^2+4x(\frac{70304}{x^2})\\ A = x^2 + \frac{281216}{x}

We want to minimize A, so

A' = 2x - \frac{281216}{x^2} =0\\\frac{2x^3-281216}{x^2}=0\\ {2x^3-281216} = 0\\x^3 - 140608=0\\x^3 = 140608\\x = 52

The second derivative test verifies that A has a minimum at this critical number:

A'' = 2+\frac{562432}{x^3}  which is positive at x = 52.

Now,

h = \frac{70304}{x^2}= \frac{70304}{(52)^2}=26

Hence, The box should have base 52 cm by 52 cm and height 26 cm.

To know more about volume, click on the link

brainly.com/question/463363

#SPJ4

8 0
2 years ago
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