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Molodets [167]
3 years ago
11

sixty more than nine times a number is the same as two less than ten times the number. what is the number

Mathematics
2 answers:
Leokris [45]3 years ago
6 0

Answer:

130

Step-by-step explanation:


Paraphin [41]3 years ago
3 0

Answer:

130

Step-by-step explanation:


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PLEASEEE HELP ME I NEED THIS ASAP
Pavel [41]

Answer:

The fourth option is the correct answer

Step-by-step explanation:

The given expression is

-2n(5+n-8-3n)

Given that n=3,We substitute the value of n into the expression and simplify.

This implies that,

-2n(5+n-8-3n)=-2(3)[5+3-8-3(3)]

=-6(5+3-8-9)

=-6(-9)

=54

Hence the answer is 54

6 0
2 years ago
Read 2 more answers
Round 519.6597 to the nearest tenth place
EleoNora [17]
To round to the nearest tenth place you are going to round the last two digits of that, you should get 519.7
8 0
3 years ago
Mrs. Kennard has a circular garden with radius of 4.5 ft. she wants to put up a wood fence around half of garden and a steel fen
sveticcg [70]

Answer:108.33, assuming that the wood fence goes around the garden and doesn’t cut across it as well

Step-by-step explanation: 4.5 times 2 times pi to find circumference. Divide by 2 because it is only half of garden. Times by 12 to convert to inches. Divide by 36. Multiply by 23.

6 0
2 years ago
1. In an auditorium, there are 21 seats in the first row and 26 seats in the second row. The number of seats in a row continues
kondor19780726 [428]
1. Let s_n be the number of seats in the n-th row. The number seats in the n-th row relative to the number of seats in the (n-1)-th row is given by the recursive rule

s_n=s_{n-1}+5


Since s_1=21, we have

s_2=s_1+5
s_3=s_2+5=s_1+2\cdot5
s_4=s_3+5=s_1+3\cdot5
\cdots
s_n=s_{n-1}+5=\cdots=s_1+(n-1)\cdot5

So the explicit rule for the sequence s_n is

s_n=21+5(n-1)\implies s_n=5n+16

In the 15th row, the number of seats is


s_{15}=5(15)+16=91

2. Let p_n be the amount of profit in the n-th year. If the profits increase by 6% each year, we would have

p_2=p_1+0.06p_1=1.06p_1
p_3=1.06p_2=1.06^2p_1
p_4=1.06p_3=1.06^3p_1
\cdots
p_n=1.06p_{n-1}=\cdots=1.06^{n-1}p_1

with p_1=40,000.

The second part of the question is somewhat vague - are we supposed to find the profits in the 20th year alone? the total profits in the first 20 years? I'll assume the first case, in which we would have a profit of


p_{20}=1.06^{19}\cdot40,000\approx121,024

3. Now let p_n denote the number of pushups done in the n-th week. Since 3\cdot4=12, 12\cdot4=48, and 48\cdot4=192, it looks like we can expect the number of pushups to quadruple per week. So,

p_n=4p_{n-1}

starting with p_1=3.

We can apply the same reason as in (2) to find the explicit rule for the sequence, which you'd find to be

p_n=4^{n-1}p_1\implies p_n=4^{n-1}\cdot3
6 0
3 years ago
What is the missing step in the given proof?
Anon25 [30]
<span>Statement: ∠7 and ∠8 are supplementary.
Reason: Linear Pair Theorem</span>
8 0
3 years ago
Read 2 more answers
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