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3 years ago

Determine whether 25a^2 − 49b^6 is a difference of two squares. If so, factor it. If not, explain why.

Mathematics

1 answer:

My name is Ann [436]3 years ago

7 0

It is the difference of 2 squares as its of the form a^2 - b^2

A is the correct answer.

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26 and please show work last one thank u

Norma-Jean [14]

I would say 28 or 25 it's one of them I forgot it

7 0

3 years ago

(2x+y=-2<br> 5x + 3y = -8<br> Solve by elimination

Effectus [21]

Answer:

y = -6, x =2

Step-by-step explanation:

To solve by elimination, you have to line both equations up together. Then, you multiply both equations until one variable is removed.

2x+y = -2

5x + 3y = - 8

There are many different ways to solve an elimination problem, but generally you should look for the simplest route. Here, I would multiply the top equation by -3.

-6x -3y = 6

5x +3y = -8

Imagine you are adding the two equations together. You end up with

-x = -2

Then solve for x. In this situation, it is fairly simple. Take out a factor of -1.

x = 2

Finally, choose one of your beginning equations and plug your new-found x value back into the equation.

2(2) +y = -2

4 + y = -2

y = -6

8 0

3 years ago

Help me fast now now now now

My name is Ann [436]

Answer:

Maybe 10.5?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the flux of the following vector fields across the given surface with the specified orientation. You may use either an expl

BlackZzzverrR [31]

The tetrahedron passes through the intercepts (5, 0, 0), (0, 2, 0), and (0, 0, 10). Parameterize the surface (call it $\Sigma$ ) by

$\vec r(u,v)=(1-v)\langle5,0,0\rangle+v\left((1-u)\langle0,2,0\rangle+u\langle0,0,10\rangle\right)$

$\vec r(u,v)=\langle5(1-v),2(1-u)v,10uv\rangle$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $\Sigma$ to be

$\vec r_v\times\vec r_u=\langle20v,50v,10v\rangle$

Then the flux of $\vec F(x,y,z)=\langle x,y,z\rangle$ across $\Sigma$ is

$\displaystyle\iint_\Sigma\vec F\cdot\mathrm d\vec S=\int_0^1\int_0^1\langle5(1-v),2(1-u)v,10uv\rangle\cdot\langle20v,50v,10v\rangle\,\mathrm du\,\mathrm dv$