Given:
Uniform distribution of length of classes between 45.0 to 55.0 minutes.
To determine the probability of selecting a class that runs between 51.5 to 51.75 minutes, find the median of the given upper and lower limit first:
45+55/2 = 50
So the highest number of instances is 50-minute class. If the probability of 50 is 0.5, then the probability of length of class between 51.5 to 51.75 minutes is near 0.5, approximately 0.45. <span />
Answer:
We have sufficient evidence to conclude at α = .05 that the husband’s perception would be higher than the wife’s.
Step-by-step explanation:
The hypotheses testing procedure in the given scenario is
H0: Husband’s perception would be similar to the wife’s i.e. μh=μw
Ha: Husband’s perception would be higher than the wife’s i.e. μh>μw
Level of significance: α=0.05
Test statistic: t=2.776
Critical region: t>t(0.05,9)=1.833
Conclusion: As the calculated value of t lies in critical region, so we reject our null hypothesis at 0.05 level of significance. Thus, we have sufficient evidence to conclude at α = .05 that the husband’s perception would be higher than the wife’s.
Answer:
5x² - 10x - 15 = 0
Step-by-step explanation:
Given that the roots are x = 3 and x = - 1, then the factors are
(x - 3) and (x + 1) and the quadratic is the product of the factors, that is
f(x) = a(x - 3)(x + 1) ← a is a multiplier
Here a = 5, thus
f(x) = 5(x - 3)(x + 1) ← expand factors using FOIL
= 5(x² - 2x - 3) ← distribute parenthesis by 5
= 5x² - 10x - 15
Thus equation is
5x² - 10x - 15 = 0
Answer:
11 dimes equals 110
Step-by-step explanation:
so you have 3.45 cents.
First one!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11111111111111111111111111111111111111
