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Schach [20]
3 years ago
15

The average distance from the sun to Venus is 67,237,910 miles. The average distance from the sun to earth is 92,955,807 miles

Mathematics
2 answers:
Mumz [18]3 years ago
6 0
C - the value of 2 in Venus' distance is 1/10 the value of earth's distance.

The 2 in Venus' distance represents 200,000
The 2 in Earth's distance represents 2,000,000
murzikaleks [220]3 years ago
3 0
Find the difference, so subtract the two and you should get the answer from earth to Venus
You might be interested in
What is the inverse of f(x)=4x+3 ?
GaryK [48]
<h2>Steps:</h2>

Here are the steps to convert an equation to its inverse:

  1. Change f(x) to y
  2. Switch the positions of x and y
  3. Solve for y
  4. Change y to f^-1(x)

Firstly, do the first two steps:

x=4y+3

Next, let's solve for y. Subtract 3 on both sides:

x-3=4y

Next, divide both sides by 4:

\frac{1}{4}x-\frac{3}{4}=y

<h2>Answer:</h2>

Finally, change y to f^-1(x) and your final answer will be:

f^{-1}(x)=\frac{1}{4}x-\frac{3}{4} , or <u>the second option.</u>

7 0
3 years ago
How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
If you are calculating 15% off a discount you need to
katrin2010 [14]
You will need to subtract if u are taking 15% off
7 0
2 years ago
3x-12/x^2+10x+24 ÷ x^2-16/x^2+6x.​
ludmilkaskok [199]

Answer:

19x^3 -4 all divided by x^2

Step-by-step explanation:

It would be greatly appreciated if you gave me the brainlest

7 0
2 years ago
Cual es el valor de un esfero cuando la docena se compra en $7848? Area de un triangulo de 9 unidades de base y 6 unidades de al
aniked [119]

Answer:

a) $654

b) 27 unidades cuadradas

c) 721

Step-by-step explanation:

a) ¿Cuál es el valor de un bolígrafo cuando la docena se compra por $ 7848?

Una docena = 12

Por eso:

12 bolígrafos = $ 7848

1 bolígrafo = $ x

Cruz multiplicar

12 bolígrafos × $ x = 1 bolígrafo × $ 7848

$ x = 1 bolígrafo × $ 7848/12

$ x = $654

b) Área de un triángulo ¿9 unidades de base y 6 unidades de altura?

Área de un triángulo =

= 1/2 × Base × Altura

1/2 × 9 × 6

= 27 unidades cuadradas

c) Cien veces la suma de 4.5 con 2.71

Esto se calcula como:

100 × (4,5 + 2,71)

= 100 × (7.21)

= 721

6 0
2 years ago
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