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larisa [96]
3 years ago
11

The wait time to ride the thunder boats is 30 minutes when 180 people are in line. Write and solve a proportion to find the wait

time when 240 people are in line
Mathematics
1 answer:
mars1129 [50]3 years ago
6 0
SO EASY 60 people = 10 minutes in line 240 people = 40 minutes in line
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If h(x) = x – 7 and g(x) = x2, which expression is equivalent to(g*h)(5)? a (5 – 7)2, b (5)2 – 7, c (5)2(5 – 7), d (5 – 7)x2
asambeis [7]
H(x) = x - 7
g(x) = x^2
(g * h)(x) = x^2 (x - 7)
(g * h)(5) = 5^2 (5 - 7)
8 0
2 years ago
9. The ages of A and B are in the ratio 3:5. Four years later,
Tom [10]

Answer:

A = 15  B = 25       in four years  19+29 = 48

Step-by-step explanation:

age A and B ratio is 3 to 5

A+4 + B+4 = 48

    A + B  = 40

    A/B = 3/5     A = 3B/5

    A + B  = 40

 3B/5 + B  = 40

   3B  + 5B = 200          multiple both sides by 5

       8B  = 200

         B  =  25

         A  = 3B/5

         A  = 3(25)/5

         A  = 15

8 0
3 years ago
Read 2 more answers
HELP PLEASE????!!!! ASAP!!!!!!
Salsk061 [2.6K]
The slope is the amount it will cost you per mile, in addition to the flat fee represented by the y-intercept.  (The cost before driving any miles.)

So b. is the  correct answer as;

$25 is the cost per day to rent the car and $0.15 is the cost per mile.
8 0
3 years ago
Read 2 more answers
"the advrage a of 2 numbers c and d is equal to half the sum of c and d " this whole qustion confuses the I am basically suppose
olga_2 [115]

Answer:

\frac{c + d}{2}

Step-by-step explanation:

this is the equation used to find the average of two numbers.

8 0
2 years ago
A rock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft. How much time does it take for the r
Bogdan [553]
Check the picture below.

so it hits the ground when y = 0, thus

\bf ~~~~~~\textit{initial velocity}\\\\
\begin{array}{llll}
~~~~~~\textit{in feet}\\\\
h(t) = -16t^2+v_ot+h_o
\end{array} 
\quad 
\begin{cases}
v_o=\stackrel{16}{\textit{initial velocity of the object}}\\\\
h_o=\stackrel{5}{\textit{initial height of the object}}\\\\
h=\stackrel{}{\textit{height of the object at "t" seconds}}
\end{cases}

\bf h(t)=-16t^2+16t+5\implies \stackrel{h(t)}{0}=-16t^2+16t+5
\\\\\\
16t^2-16t-5=0\implies (4t+1)(4t-5)=0\\\\
-------------------------------\\\\
4t+1=0\implies 4t=-1\implies t=-\cfrac{1}{4}\\\\
-------------------------------\\\\
4t-5=0\implies 4t=5\implies t=\cfrac{5}{4}\implies \boxed{t=1\frac{1}{4}}

since "t" is seconds it took, it can't be a negative amount.

5 0
3 years ago
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