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Mekhanik [1.2K]
3 years ago
14

Find the values of a , b and c in the equation below

Mathematics
1 answer:
stellarik [79]3 years ago
5 0

Answer:

x^12 y^2 z^11

a= 12

b= 2

c= 11

Step-by-step explanation:

On the numerator you distribute the exponent 3 to the other exponents.

I think you multiply the 3 so you would get: x^15 y^3 z^12.

so it looks like x^15 y^3 z^12 / x^3yz

Then you subtract the top exponents from the bottom exponent because when you are dividing you subtract exponents. the exponent for y and z in the denominator is 1

and thats how i got x^12 y^2 and z^11. The exponents are a b and c

I hope that is right

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Answer:

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Step-by-step explanation:

Given the expression

\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)

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Add similar elements        

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Add similar elements        

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Thus, the equivalent expression in simplified form:

\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1

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Hope that helps! :)
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