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Mekhanik [1.2K]
4 years ago
14

Find the values of a , b and c in the equation below

Mathematics
1 answer:
stellarik [79]4 years ago
5 0

Answer:

x^12 y^2 z^11

a= 12

b= 2

c= 11

Step-by-step explanation:

On the numerator you distribute the exponent 3 to the other exponents.

I think you multiply the 3 so you would get: x^15 y^3 z^12.

so it looks like x^15 y^3 z^12 / x^3yz

Then you subtract the top exponents from the bottom exponent because when you are dividing you subtract exponents. the exponent for y and z in the denominator is 1

and thats how i got x^12 y^2 and z^11. The exponents are a b and c

I hope that is right

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7 0
3 years ago
An apartment complex has a floor plan with dimensions shown. To effectively air condition a room, 20 BTU’s are required for ever
kifflom [539]

12,900 BTU's are required to cool the room effectively.

Step-by-step explanation:

Step 1:

We must calculate the area of the entire shape to determine the minimum BTU's required to cool the room effectively.

It is made up of a semi-circle a rectangle, and a trapezoid.

Step 2:

The area of a semi-circle =\frac{ \pi r^{2} }{2} .

Here, the diameter is 20 feet so the radius is 10 feet.

The area of the semi-circle =\frac{ \pi r^{2} }{2} =\frac{ (\pi) (10^{2}) }{2} = 157.079 square feet.

The area of a rectangle = (l)(w).

The length of the rectangle is 22 feet and the width is 20 feet.

The area of a rectangle = (l)(w) =(22)(20) = 440 square feet.

The area of a trapezoid =\frac{a+b}{2} (h).

Here a=12, b= 20, h= 3.

The area of a trapezoid =\frac{12+20}{2} (3) = 48 square feet.

Step 3:

The total area of the floor plan =157.079+440+48 = 645.079 square feet.

If 20 BTU's are required for a single square foot,

The number of BTU's for 645.079 square feet = (645.079)(20)=12,901.58 BTU's.

Rounding this off, we get 12,900 BTU's required  to cool the room effectively.

7 0
3 years ago
Cole rode his bike twice as far as Anita did today. Is this situation modeled by an expression or equation? How do you know?
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Answer:

equation

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Y = 2X

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8 0
3 years ago
Jerry, an electrician, worked 7 months out of the year. What percent of the year did he work? (Round answer to the nearest hundr
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6 0
3 years ago
5x + 4y = 11<br> 2x + 6y = -7
olga55 [171]

\left\{\begin{array}{ccc}5x+4y=11&|\cdot2\\2x+6y=-7&|\cdot(-5)\end{array}\right\\\underline{+\left\{\begin{array}{ccc}10x+8y=22\\-10x-30y=35\end{array}\right}\ \ \ \ |add\ both\ sides\ of\ the\ equations\\.\ \ \ \ \ \ \ \ \ \ \ -22y=57\ \ \ \ |:(-22)\\.\ \ \ \ \ \ \ \ \ \ \ y=-\dfrac{57}{22}\\\\substitute\ the\ value\ of\ y\ to\ the\ first\ equation\\\\5x+4\left(-\dfrac{57}{22}\right)=11\\\\5x-2\cdot\dfrac{57}{11}=11\ \ \ \ |\cdot11\\\\55x-114=121\ \ \ \ |+114\\\\55x=135\ \ \ \ |:55

x=\dfrac{135}{55}\\\\x=\dfrac{27}{11}\\\\Answer:\ x=\dfrac{27}{11}\ and\ y=-\dfrac{57}{22}\to\left(\dfrac{27}{11},\ -\dfrac{57}{22}\right)

8 0
3 years ago
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