Answer:Consider the right triangle formed by the complex number in the Argand-Gauss plane and it's projections on the axis. – José Siqueira Nov 12 '13 at 17:21
In particular what is the definition of sine of theta in terms of the known sides of the above mentioned right triangle? – Adam Nov 12 '13 at 17:27
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3 Answers
1
Consider the following Argand-diagram
enter image description here
The y-axis is the imaginary axis and the x-axis is the real one. The complex number in question is
x+yi
To figure out θ, consider the right-triangle formed by the two-coordinates on the plane (illustrated in red). Let θ be the angle formed with the real axis.
tanθ=yx
⟹tan−1(yx)
The hypotenuse of the triangle will be
x2+y2−−−−−−√
Therefore,
Step-by-step explanation:
Answer:
A: The plant grows 1CM every day
Step-by-step explanation:
Answer:
Amount she would have in 2 years at a simple interest of is
$5000 + ($5000 x 0.048 x 2) = $5480
Amount she would have in 2 years at a 4.1 % / year compounded semi- annually is :
$5000 x ( 1 +0.041/2)^4 = $5422.78
the first option yields a higher value in two years when compared with the second option. Thus, the first option is the best one to choose
Step-by-step explanation:
Future value with simple interest = principal + interest
Interest = principal x interest rate x time
0.048 x 5000 x 2 = 480
future value = $480 + 5000 = $5480
The formula for calculating future value with compounding:
FV = P (1 + r)^nm
FV = Future value
P = Present value
R = interest rate
m = number of compounding
N = number of years
5000 x ( 1 + 0.041 / 2)^(2 x 2) = $5422.78
Answer:
Square
Step-by-step explanation:
The length of AB is (a+b)-a = b. The length of BC is b-0 = b. So, adjacent sides are the same length. AB has a constant y-value, so is horizontal. BC has a constant x-value, so is vertical.
A figure with horizontal and vertical sides of the same length is a square.
Answer:
A maximum of 43 students and 11 teachers can go to the trip.
Step-by-step explanation:
Since a group of teachers and students will take a bus trip to a museum, and each teacher will lead a group of no more than 4 students, and the bus can hold a maximum of 54 teachers and students, to determine the possible numbers of teachers and students who can go on the trip, the following calculation must be performed:
4 + 1 = 5
54/5 = X
10.8 = X
10 x 4 = 40
10 x 1 = 10
4 - 1 = 3
Therefore, a maximum of 43 students and 11 teachers can go to the trip.
