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3 years ago

Simplify the expression 2(8.8x + 17.6)-4.3. what is the constant in the simplified expression

Mathematics

1 answer:

Korolek [52]3 years ago

7 0

Answer: 17.6x +30.9

Step-by-step explanation:

the constant is 30.9

1) you distribute the 2 to 8.8. and 17.6

2) then you combine like terms

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16.1555

Step-by-step explanation:

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3 years ago

How do you Solve <br><br> 24=6(-x-3)

jok3333 [9.3K]

You use the distributive prop. Then you add 18 to both sides and you get your answer.

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3 years ago

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Pls help me! and no files and pls actually help me

crimeas [40]

Answer:

To find m ( slope) we'll use the Slope Formula:

$\boxed{\sf{Slope\:(m)}=\cfrac{y_2-y_1}{x_2-x_1}}$

<u>Subtract the numbers:-</u>

$\sf 7. \:m=\cfrac{4-2}{6-5} =\boxed{2}$

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$\sf 8.\: m=\cfrac{-1-3}{2-6} =\boxed{1}$

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$\sf 9.\: m=\cfrac{-4-(-2)}{3-1} =\boxed{-1}$

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$\sf 10.\: m=\cfrac{0-3}{0-(-3)} =\boxed{-1}$

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$\sf 11.\:m=\cfrac{4-2}{3-1} =\boxed{1}$

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$\sf 12.\: m=\cfrac{1-7}{2-5} =\boxed{2}$

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$\sf 13.\:m=\cfrac{11-9}{1-(-4)} =\boxed{\frac{2}{5}}$

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$\sf 14.\:m=\cfrac{2-3}{3-5} =\boxed{\frac{1}{2}}$

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$\sf 15.\: m=\cfrac{11-5}{2-9} =\boxed{-\frac{6}{7}}$

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$\sf 16.\: m=\cfrac{-7-\left(-6\right)}{8-13}=\boxed{\frac{1}{5}}$

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$\sf 17.\: m=\cfrac{4-4}{6-1} =\boxed{0}$

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$\sf 18. \: m=\cfrac{2-(-7)}{5-5}=$

↑ Undefined

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6 0

3 years ago

WILL MARK BRAINLIEST! Please help!

Lelu [443]

you can put both sides of the equation to the 4th power

$( \sqrt[4]{d - 15}) ^{4} = (2)^{4}$

$d - 15 = 16$

$d = 31$

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4 years ago

Evaluate the integral:

Bogdan [553]

Substitute x = √7 sin(t) and dx = √7 cos(t) dt. Then

∫ √(7 - x²) dx = ∫ √(7 - (√7 sin(t))²) • √7 cos(t) dt

… = √7 ∫ √(7 - 7 sin²(t)) cos(t) dt

… = 7 ∫ √(1 - sin²(t)) cos(t) dt

… = 7 ∫ √(cos²(t)) cos(t) dt

We require that -π/2 ≤ t ≤ π/2 in order for the substitution we made to be reversible. Over this domain, cos(t) ≥ 0, so

√(cos²(t)) = |cos(t)| = cos(t)

and the integral reduces to

… = 7 ∫ cos²(t) dt

Recall the half-angle identity for cosine:

cos²(t) = (1 + cos(2t))/2

Then the integral is

… = 7/2 ∫ (1 + cos(2t)) dt

… = 7/2 (t + 1/2 sin(2t)) + C

… = 7t/2 + 7/4 sin(2t) + C

Get the antiderivative back in terms of x. Recall the double angle identity for sine:

sin(2t) = 2 sin(t) cos(t)

We have t = arcsin(x/√7), which gives

sin(t) = sin(arcsin(x/√7)) = x/√7

cos(t) = cos(arcsin(x/√7)) = √(7 - x²)/√7

Then

∫ √(7 - x²) dx = 7/2 arcsin(x/√7) + 7/4 • 2 sin(arcsin(x/√7)) cos(arcsin(x/√7)) + C

… = 7/2 arcsin(x/√7) + x/2 √(7 - x²) + C

5 0

2 years ago