Write two addition equations that each have a sum of -21.5

Mathematics

1 answer:

blondinia [14]3 years ago

6 0

Answer:

-8.5 + -13 = -21.5

and

-15.5 + -6 = -21.5

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40 POINTS answer correctly

Alexxx [7]

Since the denominator is the number on the bottom, we need to find a common denominator for a and 5a^2. Since a*5a is 5a^2, we have a common denominator - 5a^2! For the fractions, that means that since a*5a=5a^2, we have to multiply -7 by 5a to get -35a/5a^2-9/5a^2=(-35a-9)/5a^2

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Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by (-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.

An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.

Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.

Substituting C(2, 2) into the system we have:
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as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.

Part C:
Given that Natalie can only attend a school in her designated zone and that Natalie's zone is defined by y < −2x + 2.

To identify the schools that Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.

For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true

For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true

For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false

For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true

For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false

For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.

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If we us the method asquared + b squared =c squared x=8 cuz
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