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3 years ago

Please Help! I have to finish this in 30 mins!

Mathematics

2 answers:

crimeas [40]3 years ago

8 0

Answer:justin can

Step-by-step explanation:

zzz [600]3 years ago

3 0

Justin can !! If I’m too late for you sorry but I’m sure someone else could Use this

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Find the LCM of the set of numbers 4 5 6

Fed [463]

Answer:

C dont trust me wait for someone else to anser

Step-by-step explanation:

4 0

2 years ago

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Assuming that a soap bubble is a perfect sphere, what is the diameter of a bubble containing 1,000 cm^3 of air? Round to the nea

jenyasd209 [6]

Answer:

A is correct

Step-by-step explanation:

In this question, we are concerned with. calculating the diameter of a bubble given the volume of the bubble.

Since we have assumed the bubble to be a perfect sphere, it’s volume V = 4/3 * pi * r^3

Plugging the value of V = 1000cm^3 , we have

1000 = 4/3 * pi * r^3

3000/4pi = r^3

r^3 = 238.732

r = cube foot of 238.732

r = 6.20cm

This is same as 6.2cm

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3 years ago

What is the distributive property of 36÷3

olya-2409 [2.1K]

12 is the answer your looking for

7 0

2 years ago

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PLSSS ANSWER WILL GIVE BRAINLIEST

Korolek [52]

Answer:

a. Positive

b. Negative

c. Negative

d. Positive

Step-by-step explanation:

I hope this helps! May I please have brainliest? :)

8 0

3 years ago

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Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting

stealth61 [152]

Answer:

Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$ and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

Thus, Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

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2 years ago

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