Help por favor!! please

Can you please give me an answer to this question like so

kari74 [83]

Answer:
(i) C
(ii) C
(iii) A
(iv) A

8 0

3 years ago

Which equations are true? Choose all answers that apply: Choose all answers that apply: (Choice A) A -x +0+(- x) = 0−x+0+(−x)=0m

lora16 [44]

Answer:

(B)-x-(-x) =0

Step-by-step explanation:

<u>Option A</u>

Our equation is: -x +0+(- x) = 0

Left Hand Side:

-x +0+(- x) = -x-x=-2x

$($Left Hand Side) $-2x\neq 0$ (Right Hand Side)$

<u>Option B</u>

Our equation is: -x-(-x) =0

Left Hand Side:

-x-(-x) =-x+x=0

$($Left Hand Side) 0 = 0 (Right Hand Side)$

Therefore, the equation in Option B is true.

3 0

3 years ago

5(x−3) 2 +4=<br> answer plz

Kryger [21]

Answer:

The answer is 10x-26 or try using the Distributive Property.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

5-4. Solve each of the following equations for the indicated variable. Use your Equation Mat if it is helpful. Write down each o

balu736 [363]

QUESTION 1

The given equation is :

$2(y - 3) = 4$
We want to solve for y. This means we have to isolate y on one side of the equation while all other constants are also on the other side of the equation,

We first divide both sides by 2 to obtain,

$\frac{2(y - 3)}{2} = \frac{4}{2}$

We cancel out the common factors to get,

$y - 3 = 2$

We now group like terms to get,

$y = 3 + 2$

We simplify to obtain,

$y = 5$

QUESTION 2

The given equation is

$2x + 5y = 10$
We want to solve for x. This means that we need to isolate x on one side of the equation, while all other variables and constant are also on the other side of the equation.

This implies that,

$2x= 10 - 5y$

We now divide through by 2, to obtain,

$\frac{2x}{2} = \frac{10}{2} - \frac{5y}{2}$

This will now give us,

$x = 5 - \frac{5}{2} y$

QUESTION 3

The given equation is
$6x + 3y = 4y + 11$

We want to solve for y. This means that we need to isolate y on one side of the equation, while all other variables and constants are also on the other side of the equation.

We first of all group all the y terms on one side of the equation to obtain,

$6x - 11 = 4y - 3y$

We simplify to get,

$6x - 11 = y$

This implies that,

$y = 6x - 11$

QUESTION 4

The given equation is,

$3(2x + 4) = 2 + 6x + 10$

We want to solve for x. This means that we need to isolate x on one side of the equation, while all other variables and constant are also on the other side of the equation.

Let us first expand the brackets to get,

$6x + 12 = 2 + 6x + 10$
This implies that

$6x + 12 = 6x + 12$

We group like terms to get,

$6x - 6x = 12 - 12$

We now simplify both sides to get,

$0x = 0$

We don't want x to vanish, so let us try to divide both sides by zero to get,

$x = \frac{0}{0}$

This is an indeterminate form, which implies that, x has infinitely many solutions. This means that all the real numbers are solution to the equation.

$\therefore \: x \in \: R$

QUESTION 5

The given equation is,

$y = - 3x + 6$

We want to solve for x, so we add the additive inverse of 6, which is -6 to both sides of the equation to get,

$y - 6 = - 3x$

We rewrite this to obtain,

$- 3x = y - 6$

We divide through by -3 to get,

$\frac{ - 3x}{ - 3} = \frac{y}{ - 3} - \frac{6}{ - 3}$

This will give us,

$x = - \frac{y}{3} + 2$

or

$x= 2 - \frac{1}{3} y$

5 0

3 years ago

For the past 15 months, Frank recorded the cost of his monthly home heating bill and the corresponding average monthly temperatu

leonid [27]

The scatter plot shows that the heating bill will be about $95 for an average monthly temperature of 40°F.

<h3>What is a scatter plot?</h3>

It should be noted that a scatter plot uses dots to represent values for different numeric variables. In this case, the position of each dot on the horizontal and vertical axis shows the values for an individual data point.

From the complete question, the graph attached shows that the heating bill will be about $95 for an average monthly temperature of 40°F.

In conclusion, scatter plots are used to observe the relationships between variables.

Learn more about scatter plots on:

brainly.com/question/6592115

3 0

2 years ago