See the image below.
Here are the points to remember.
1. The number of protons (atomic number) is the same whether an atom is neutral or ionic.
2. In a neutral atom, the number of electrons = the number of protons.
3. The number of electrons in each shell is 2, 8, 8, 18, 18, …
4. The number of electrons in an atom at the end of each period (a noble gas) is 2, 10, 18, 36, 54, …
5. An atom will gain or lose electrons to achieve a noble gas configuration.
For example, a potassium atom has 19 protons and 10 electrons. It will form an ion by losing one electron to get to 18 electrons.
The molal concentration of the solution is 0.67 mol/kg.
The formula for molal concentration (<em>b</em>) is
<em>b</em> = moles of solute/kilograms of solvent.
Moles of solute = 8.0 g × (1 mol/24 g) = 0.333 mol
b = 0.333 mol/0.50 kg = 0.67 mol/kg
Answer: 6.18 g/L
Explanation:
To calculate the density of gas, we use the equation given by ideal gas equation:
Number of moles (n) can be written as:
where, m = given mass
M = molar mass
where,
which is known as density of the gas
The relation becomes:
.....(1)
We are given:
M = molar mass of = 146.06 g/mol
R = Gas constant =
T = temperature of the gas =
P = pressure of the gas = 1 atm
Putting values in equation 1, we get:
Thus density of sulfur hexafluoride gas at exactly 15°C and exactly 1atm is 6.18g/L
The spheres representing nitrogen and oxygen are different colors because they are distinct atoms.
Answer:
by using ideal gas law
Explanation:
ideal gas law:
PV=nRT
where:
P is pressure measured in Pascal (pa)
V is volume measured in letters (L)
n is number of moles
R is ideal gas constant
T is temperature measured in Kelvin (K)
by applying the given:
P(initial) V(initial)=nRT(initial)
P(final) V(final)=nRT(final)
nR is constant in both equations since same gas
then,
P(initial) V(initial) / T(initial) = P(final) V(final) / T(final)
then by crossing multiply both equations
V (final)= { (P(initial) V(initial) / T(initial)) T(final) } /P (final)
P(initial)=P(final)= 1 atm = 101325 pa
V(initial)= 6 L
T(initial) = 28°c = 28+273 kelvin
T(final) = 39°c = 39+273 kelvin
by substitution
V(final) = 6.21926 L