Answer:
a) gold - Solid
b) gasoline - liquid
c) oxygen - gaseous
d) olive oil - liquid
e) mercury (found in thermometers) - liquid
f) aluminum - solid
Explanation:
Matter exists in three states viz: solid, gas and liquid. Note that, room temperature is a neither hot or cold temperature, which is about 20-23°C.
A) Gold is a transition metal with the symbol Au. At a room temperature, Gold, like most metals are found as SOLIDS.
B) Gasoline is a liquid mixture of refined hydrocarbons majorly used as fuels.
C) Oxygen is a chemical element with symbol O. It is a constituent of natural air, which is a mixture of different gases including oxygen. Hence, at room temperature, Oxygen is a gas.
D) Olive oil is a vegetable oil got from olives. It is composed of fats and it's a liquid at room temperature.
E) Mercury is an element with symbol Hg. It is the only metallic element found naturally (at room temperature) as a liquid. It is used in thermometers.
F) Aluminum is another chemical element with symbol Al. It is a lustrous metal that occurs as a Solid in room temperature.
4: The mass amount of protons and neutrons in an atom
We just covered this in my chem class
Answer:
4.27
Explanation:
Let's consider the dissociation of a generic monoprotic acid.
HA(aq) → H⁺(aq) + A⁻(aq)
The pH is 2.36. The concentration of H⁺ is:
pH = -log [H⁺]
[H⁺] = antilog -pH
[H⁺] = antilog -2.36 = 4.37 × 10⁻³ M
We know that the concentration of the acid Ca = 0.3535 M. We can find the acid dissociation constant using the following expression.
[H⁺] = √(Ca × Ka)
Ka = [H⁺]²/Ca
Ka = (4.37 × 10⁻³)²/0.3535
Ka = 5.40 × 10⁻⁵
The pKa is:
pKa = -log Ka = -log 5.40 × 10⁻⁵ = 4.27
Answer:
15 h
Explanation:
Okay, the first thing that we all have to know before we can answer this question is that this Topic that is, Chemistry of Radioactivity is related to kinetics in a way that Radioactive disintegration follows the first order of Reaction which is under kinetics. So, we will be using the first order kinetics rate law to answer this question. Using the equation (1) below;
k =[ 2.303/ t ]×log ([N°}/ [Nr]) --------(1).
We are given from the question that N° = initial sample = 0.8 mg and Nr= sample remaining = 0.2 and the time taken = t= 30.0 h.
k= (2.303/ 30.0 h ) × log (0.8/0.2).
k=0.076768 h^-1 × log (4).
k= 0.076768 h^-1 × 0.6021.
k= 0.0462 h^-1.
Therefore, using the formula for Calculating half life below for first order kinetics we will be able to find out answer.
k = ln 2/ t(1/2). Where t(1/2) is the half life.
t(1/2) = ln 2/ k.
t(1/2) = ln 2 / 0.0462 h^-1.
t(1/2)= 0.6931/0.0462 h^-1.
t(1/2)=15 h
The heated soup moves to the tip by convection
