Here we have to get the spin of the other electron present in a orbital which already have an electron which has clockwise spin.
The electron will have anti-clockwise notation.
We know from the Pauli exclusion principle, no two electrons in an atom can have all the four quantum numbers i.e. principal quantum number (n), azimuthal quantum number (l), magnetic quantum number (m) and spin quantum number (s) same. The importance of the principle also restrict the possible number of electrons may be present in a particular orbital.
Let assume for an 1s orbital the possible values of four quantum numbers are n = 1, l = 0, m = 0 and s = 
.
The exclusion principle at once tells us that there may be only two unique sets of these quantum numbers:
1, 0, 0, + and 1, 0, 0, -.
Thus if one electron in an orbital has clockwise spin the other electron will must be have anti-clockwise spin.
49.8 g should be the balance read.
Explanation:
Adding the mass of the evaporation dish 44.8 g with the mass of the copper 5 g you obtain 49.8 g.
On the balance you put first the evaporation dish (or a watch glass) over which you add copper until you reach 49.8 g.
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Answer:
CaCN₂
Explanation:
A compound of calcium, carbon and nitrogen CaₐCₓNₙ in oxygen will burning producing:
CaₐCₓNₙ + O₂ → aCaO + xCO₂ + nNO₂
Moles of the oxides CaO, CO₂, NO₂ are:
CaO: 3.106g ₓ (1 mole / 56.08g) = <em>0.0554 moles of CaO = moles of Ca</em>
CO₂: 2.439g ₓ (1mole / 44g) = <em>0.0554 moles CO₂ = moles C</em>
NO₂: 5.097g ₓ (1mole / 46g) = <em>0.111 moles NO₂ = moles N</em>
Empirical formula is the chemical formula that represents the simplest ratio of elements in a compound.
Having as basis 0.0554 moles (The lower number of moles):
0.0554 moles Ca / 0.0554 = 1 Ca
0.0554 moles C / 0.0554 = 1 C
0.111 moles N / 0.0554 = 2N
Thus, the compound CaₐCₓNₙ has as empirical formula:
Ca₁C₁N₂ = <em>CaCN₂</em>
