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lesantik [10]
3 years ago
10

Which complex number has an absolute value of 5?

Mathematics
2 answers:
Shkiper50 [21]3 years ago
4 0
I believe the only complex number that has the absolute value of 5 is
<span>–3 + 4i</span>
egoroff_w [7]3 years ago
4 0
|x+iy|=sqrt(x^2+y^2)
-3+4i
=
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10
shutvik [7]

Answer:15

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What dose this equal (8.5)x(-3)=a
Nana76 [90]

Answer:

-25.5

8x3=24

but we still have the .5 so we multiply that by 3 which equals to 1.5 add that to 24 which makes 25.5 and because only one of the numbers was negative it turns 25.5 into -25.5.

5 0
3 years ago
Translate the sentence into an inequality twice the difference of a number and 6 is at least -22 use the variable x for the unkn
almond37 [142]

Answer:

2(n - 6) >= 22

Step-by-step explanation:

2n - 12 >= 22

2n >= 22+12

2n >= 34

n >= 34/2

n >= 17

5 0
3 years ago
Simplify
denis23 [38]

Hello!

<u><em>Answer: </em></u>

<u><em>1. =-6</em></u>

<u><em>2. =39</em></u>

<u><em>3. =-603</em></u>

_________________________________________________

Explanation: This question's it's about the order of operations. It stands for p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtract. It can also go left to right. (PEMDAS)

1. -4(3-1)+2

Do parenthesis first.

(3-1)=2

-4*2+2

Then do multiply left to right.

-4*2=-8

Add left to right.

-8+2

8-2=6

*Answer should be have negative sign.*

Answer: → \boxed{=-6}

______________________________________________________

2. 3⋅[(30−8)÷2+2]

Do parenthesis first.

(30-8)=22

22/2+2

Then divide left to right.

22/2=11

Add left to right.

11+2=13

Multiply left to right.

3*13=39

*Answer should be have positive sign.*

Answer: → \boxed{=39}

_____________________________________________________

3. 14(1-23)2+13

Do parenthesis first.

(1-23)=-22

14(-22)*2+13

Then, you multiply left to right.

14(-22)=-308

-308*2=-616

Add/subtract left to right.

-616+13

616-13=603

*The answer must be have a negative sign*

Answer: → \boxed{=-603}

____________________________________________________________

Hope this helps!

Thank you!

Have a great day!

-Charlie

7 0
3 years ago
CONSTRUCTION You are asked to copy a segment CD, construct a segment bisector by paper folding, and label the
lilavasa [31]

The steps on the construction of a segment bisector by paper folding, and label the midpoint M is given below.

<h3>What are the steps of this construction?</h3>

1. First, one need to open a Compass so that it is said to be more than half the length of the said segment.

2. Without altering it, with the aid of the compass, do  draw an art above and also below the said line segment from one of the segment endpoints.

3. Also without altering it and with use the compass, do draw another pair of arts from the other and points. One arc will be seen above the segment and the other or the second arc will be seen below.

4. Then do draw the point of intersection that is said to exist between the pair of arts below the line segment and also in-between the pair of arts as seen  below the line segment

5. Lastly, do make use of a straight edge to link the intersection points between the both pair of arts.

Learn more about segment bisector from

brainly.com/question/24736149

#SPJ1

5 0
2 years ago
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