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3 years ago

What is 6(x-3) -4 (x-5)

Mathematics

2 answers:

vladimir1956 [14]3 years ago

6 0

Answer:

2x + 2

Step-by-step explanation:

6(x - 3) - 4(x - 5)

6*x - 6*3 - 4*x - 4 * -5

6x - 18 - 4x + 20

2x + 2

Vesnalui [34]3 years ago

4 0

Answer:

2x+2

Step-by-step explanation:

6(x-3)-4(x-5)

distribute the 6 and 4

6x-18-4x+20

add all like terms

2x+2

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How many gallon jugs will 8 quarts fill?

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Answer:

The answer is 2 quarts!(:

Step-by-step explanation:

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3 years ago

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Given that g(x)=2x^2-5. Calculate g(x+4)+2

Dimas [21]

Answer:

$2x^2+16x+29$

Step-by-step explanation:

Given that,

$g(x)=2x^2-5$

We need to find g(x+4)+2

$g(x+4)=2(x+4)^2-5\\\\=2(x^2+16+8x)-5\\\\=2x^2+32+16x-5\\\\=2x^2+16x+27$

Now,

$g(x+4)+2=2x^2+16x+27+2\\\\=2x^2+16x+29$

So, the value of $g(x+4)+2$ is $2x^2+16x+29$

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3 years ago

The sum of the exterior angles of a convex polygon, one angle at each vertex, is equal to how many degrees?

alexdok [17]

<span>The sum of the exterior angles of a polygon is always 360 degrees.
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3 years ago

I honestly don’t get how to solve this

ruslelena [56]

Answer:

Two other possible measure ments of AD and AE are

(a) Let AD = 4 units and AE = 6 units.

(b )Let AD = 2 units and AE = 3 units,

Step-by-step explanation:

In ΔABC, given

AB = 8 units, BC = 9 units, AC = 12 units,

D is on AB and E is on AC

Now, when AD = 6 and AE = 9, both ΔABC and ΔADE are similar.

Also, DB = 8 units - 6 units = 2 units,

EC = 12 units - 9 units = 3 units

⇒ $\frac{AD}{DB} = \frac{AE}{EC} = 3$

To adjust the points D and E in such a way, triangles REMAIN SIMILAR.

(a) Let AD = 4 units and AE = 6 units

Then, DB = 8 units - 4 units = 4 units,

EC = 12 units - 6 units = 6 units

⇒ $\frac{AD}{DB} = \frac{4}{4} = 1 , \\ \frac{AE}{EC} = \frac{6}{6} = 1$

⇒ $\frac{AD}{DB} = \frac{AE}{EC} = 1$

Hence, ΔABC and ΔADE are similar.

(b) Let AD = 2 units and AE = 3 units

Then, DB = 8 units - 2 units = 6 units,

EC = 12 units - 3 units = 9 units

⇒ $\frac{AD}{DB} = \frac{2}{6} = \frac{1}{3} , \\ \frac{AE}{EC} = \frac{3}{9} = \frac1}{3}$

⇒ $\frac{AD}{DB} = \frac{AE}{EC} =\frac{1}{3}$

Hence, ΔABC and ΔADE are similar.

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3 years ago

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Answer: wut the ham is this

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