What is 60/13 as a decimal?

Solve. -5 3/4-3 1/2=?

g100num [7]

Answer: -9 1/4.

Step-by-step explanation:

6 0

2 years ago

2 doctors is % of 25 doctors.

hichkok12 [17]

So then there are about 15-20 doctors

3 0

3 years ago

The prior probabilities for events A1 and A2 are P(A1) = 0.35 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(

forsale [732]

Answer:

Step-by-step explanation:

Hello!

Given the probabilities:

P(A₁)= 0.35

P(A₂)= 0.50

P(A₁∩A₂)= 0

P(BIA₁)= 0.20

P(BIA₂)= 0.05

a)

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)

Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.

b)

Considering that $P(BIA)= \frac{P(AnB)}{P(A)}$ you can clear the intersection from the formula $P(AnB)= P(B/A)*P(A)$ and apply it for the given events:

$P(A_1nB)= P(B/A_1) * P(A_1)= 0.20*0.35= 0.07$

$P(A_2nB)= P(B/A_2)*P(A_2)= 0.05*0.50= 0.025$

c)

The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:

P(B)= (A₁∩B) + P(A₂∩B)= 0.07 + 0.025= 0.095

d)

The Bayes' theorem states that:

$P(Ai/B)= \frac{P(B/Ai)*P(A)}{P(B)}$

Then:

$P(A_1/B)= \frac{P(B/A_1)*P(A_1)}{P(B)}= \frac{0.20*0.35}{0.095}= 0.737 = 0.74$

$P(A_2/B)= \frac{P(B/A_2)*P(A_2)}{P(B)} = \frac{0.05*0.50}{0.095} = 0.26$

I hope it helps!

5 0

3 years ago

A. The average yearly salary of a lawyer is $24 thousand less than twice that of an architect.

erastovalidia [21]

Answer:

The average yearly salary of the architect is $62,000 and the lawyer is $100,000.

Step-by-step explanation:

Given:

The average yearly salary of a lawyer is $24 thousand less than twice that of an architect.

Combined, an architect and a lawyer earn $ 210 thousand.

Now, to find the average yearly salary of an architect and a lawyer.

Let the average yearly salary of an architect be $x.$

So, the average yearly salary of the lawyer = $2x-24,000.$

Combined, architect and lawyer earn = $\$210,000.$

Now, to get the average salary of the architect and lawyer:

$x+(2x-24000)=210000$

$x+2x-24000=210000\\\\3x-24000=210000$

Adding both sides 24000 we get:

$3x=186,000\\\\Dividing\ both\ sides\ by\ 3\ we\ get:\\\\x=62000.$

The average salary of architect = $62,000.

Now, to get the average salary of lawyer by substituting the value of $x$ :

$2x-24000\\\\=2(62000)-24000\\\\=124000-24000\\\\=\$100,000.$

The average salary of lawyer = $100,000.

Therefore, the average yearly salary of the architect is $62,000 and the lawyer is $100,000.

4 0

3 years ago

What is the value for X?

Marta_Voda [28]

X=21 and the mesure of one would be 120 to check if its correct multiply 5 by 21 then add it to 15 and that would be the answer for what 1 is you can also check of its 21 by multiplying 3 by 21 and subtracting 3 then adding both to get 180 which is the normal measurements of the line. hope this helps somehow

4 0

3 years ago