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Goryan [66]
3 years ago
8

A Chevy Malibu has a fuel capacity of 18.5 gallons. This vehicle averages 666 miles per tank. Assume the relationship between fu

el capacity (volume) and distance is linear. How many miles can this vehicle travel with 5 gallons of gasoline?​
Mathematics
1 answer:
Nuetrik [128]3 years ago
5 0

Answer:

180 miles

Step-by-step explanation:

Step one:

capacity of tank= 18.5gallons

vehicle averages 666 miles per tank.

Hence, the vehicle can travel 666 miles on 18.5 gallons

Required

The distance covered on 5 gallons

Step two:

vehicle can travel 666 miles on 18.5 gallons

the vehicle will go x miles on 5 gallons

cross multiply we have

5*666= 18.5*x

3330=18.5x

divide both sides by 18.5

x= 3330/18.5

x=180 miles

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Step-by-step explanation:

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2 years ago
A car can travel 38 miles on each gallon of gasoline how many gallons of gasoline will take to travel 190 miles
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You take 190 and divide it by 38 = 5 gallons

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3 years ago
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Recall that a 6-bit string is a bit strings of length 6, and a bit string of weight 3, say, is one with exactly three 1's. How m
strojnjashka [21]

Answer:

1.. Total number of 6 bit strings is 64

2. Number of 6-bit strings with weight of 0 is 1

3. Number of 6-bit strings with weight of 1 is 6

4. Number of 6-bit strings with weight of 3 is 20

5. Number of 6-bit strings with weight of 5 is 6

6. Number of 6-bit strings with weight of 6 is 1

7. Number of 6-bit strings with weight of 7 is 0

Step-by-step explanation:

A bit string is a string that contains 0 and 1 only

1. Total number of 6 bit strings is 2^6 = 64

2. Number of 6 bit strings with weight 0 is 1

Explanation

Weight 0 means a string with no occurrence of 1

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 0 i.e. no occurrence of 1

6C0 = 6!/(6-0)!0!

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Hence, the number of string with weight 0 (i.e. no occurrence of 1 ) is 1

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Explanation

Weight 0 means a string with exactly 1 occurrence of '1'

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 1

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n = 6 and r = 3

6C3 = 6!/(6-3)!3!

6C3 = 6!/3!3!

6C3 = 20

Hence, the number of string with weight 3 is 20

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Explanation

n = 6 and r = 5

6C5 = 6!/(6-5)!5!

6C5 = 6!/1!5!

6C5 = 6

Hence, the number of string with weight 5 is 6

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Explanation

n = 6 and r = 6

6C6 = 6!/(6-6)!6!

6C6 = 6!/0!6!

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Answer:

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