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Tpy6a [65]
3 years ago
14

I need help with this question, it is for geometry ​

Mathematics
1 answer:
expeople1 [14]3 years ago
4 0

Answer:

x=3...

Step-by-step explanation:

Given:T is the midpoint of SU.....

To find: x

Proof: ST=TU ( T is the midpoint of SU)

         8x+11=12x-1

         11+1=12x-8x

          12=4x

           12/4=x

             x=3.

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A room has eight switches, each of which controls a different light. Initially, exactly five of the lights are on. Three people
aivan3 [116]

Answer:

The probability that 3 lights are on after the third person exited the room is 39/128

Step-by-step explanation:

In order for 6 switches to be on at the end, we need exactly 2 people turning on a switch and the other one turning one off. There are 3 possibilities:

  • The first two persons turn the switch in and the last one turns it off
  • The first and last person turn the switch in and the middle one tunrns it off
  • The first person turns the switch off and the 2 remaining turn the switch in

Note that after turning off one switch one more switch will be available to be switched in and one less will be available to be switch off. The contrary happens when someone turns in a switch.

Lets calculate the probability for the first scenario. The probability for the first person to turn the switch in is 3/8, because there are 3 lights off. For the second person, there will be only 2 lights off, thus, the probability for him or her to turn the switch in is only 2/8, leaving only 1 light off and 7 on. The third person will have, as a consecuence, a probability of 7/8 to turn off one of the 7 switches. This gives us a probability of 3/8 * 2/8 * 7/8 = 21/256 for the first scenario.

For the second scenario we will have a probability of 3/8 for the first person, a probability of 6/8 for the second one (he has to turn a switch off this time), and a probability, again, of 3/8 for the third one, giving us a probability of 3/8*6/8*3/8 = 27/256 for the second scenario.

For the third scenario, the first person has to turn off the switch, and it has a probability of 5/8 of doing so. The second person will have 4 switches to turn on, so it has a probability of 4/8 = 1/2, and the third person will have one switch less, thus, a probability of 3/8 of turning a switch on. Therefore, the probability of the third scenario is 5/8*1/2*3/8 = 15/128 = 30/256

By summing all the three disjoint scenarios, the probability that six lights are on is 21/256+27/256+30/256 = 78/256 = 39/128.

8 0
2 years ago
Answer question one and show work.
likoan [24]

Answer:

x = 28

Step-by-step explanation:

angle 1 and angle 2 are complementary (their sum is 90°)

x + 5 + 2x + 1 = 90 add like terms

3x + 6 = 90 subtract 6 from both sides

3x = 84 divide both sides by 3

x = 28

3 0
2 years ago
Evaluate the following expressions using the chip method. SHOW ALL WORK!!!
Mila [183]

Answer:

  • a. -7
  • b. -20
  • c. 7

Step-by-step explanation:

  • a. -9+2, in this case, it is -7 because you take the bigger number and subtract it by the lower number. If the bigger number is negative your answer will be negative, if the bigger number is positive it will be positive it is just really a basic subtraction problem just add the sign.
  • b. In multiplication +++=+ ++-=- and a -+-=+ do your problem without thinking about the signs and then add the signs with the formula I showed you.
  • c. ---=+

Hope this helps :)!

5 0
3 years ago
PLEASE HELP!!! Name the postulate or theorem that you can use to prove.....
bearhunter [10]

Answer:

HL theorem

Step-by-step explanation:

5 0
2 years ago
Use Newton's Method to approximate the zero(s) of the function. Continue the iterations until two successive approximations diff
liubo4ka [24]

Answer:

There is only one real zero and it is located at x = 1.359

Step-by-step explanation:

After the 4th iteration the solution was repeating the first 3 decimal places.  The formula for Newton's Method is

x_{n}-\frac{f(x_{n}) }{f'(x_{n}) }

If our function is

f(x)=x^5+x-6

then the first derivative is

f'(x)=5x^4+1

I graphed this on my calculator to see where the zero(s) looked like they might be, and saw there was only one real one, somewhere between 1 and 2.  I started with my first guess being x = 1.

When I plugged in a 1 for x, I got a zero of 5/3.  

Plugging in 5/3 and completing the process again gave me 997/687

Plugging in 997/687 and completing the process again gave me 1.36976

Plugging in 1.36976 and completing the process again gave me 1.359454

Plugging in 1.359454 and completing the process again gave me 1.359304

Since we are looking for accuracy to 3 decimal places, there was no need to go further.

Checking the zeros on the calculator graphing program gave me a zero of 1.3593041 which is exactly the same as my 5th iteration!

Newton's Method is absolutely amazing!!!

5 0
3 years ago
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