Show that x+3 is a factor of f(x)=3x^4-3x^3-36x^2
1 answer:
F(x) = 3x^4 - 3x³ - 36x² f(x + 3) = 3(x + 3)^4 - 3(x + 3)³ - 36(x + 3)² f(x + 3) = 3((x + 3)(x + 3)(x + 3)(x + 3)) - 3((x + 3)(x + 3)(x + 3)) - 36((x + 3)(x + 3)) f(x + 3) = 3((x² + 6x + 9)(x² + 6x + 9)) - 3(x² + 6x + 9)(x + 3) - 36(x² + 6x + 9) f(x + 3) = 3(x^4 + 12x³ + 54x² + 108x + 81) - 3(x³ + 9x² + 27x + 27) - 36(x² + 6x + 9) f(x + 3) = 3x^4 + 33x³ + 99x² + 27x - 162
You might be interested in
Answer:
600
Step-by-step explanation:
because 60x10=600
Answer:
5/51 or 0.098
Step-by-step explanation:
A whole number that would support Cindys claim would be 2 because if u do the ,math it would be 8/24 which would be .333 repeating which is simplify to 1/3 and i do not know a number that would not work.
I should be A hope this helps
Answer: D. 72°
Step-by-step explanation: