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Karolina [17]
3 years ago
14

Caleb and Sarah are having a Halloween

Mathematics
1 answer:
Norma-Jean [14]3 years ago
4 0

I’m gonna need how many pounds of candy they have to solve this question. You didn’t say how much pounds they had

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A traffic helicopter descends 102 meters to be 331 meters above the ground, as illustrated in the diagram to the right. Write an
lana66690 [7]

Answer:

  • h -102 = 331
  • h = 433

Step-by-step explanation:

Using the problem statement as the basis for the equation, we can write ...

  h -102 = 331

__

Using the diagram as the basis for the equation, we could write it as ...

  h = 331 +102

__

The original height of the helicopter was 433 m.

3 0
3 years ago
Yosef can eat 21 jamuns while Rose can eat just 15.
Gennadij [26K]

Answer:

40%

Step-by-step explanation:

1+.40=1.4

1.4 x 15 = 21

7 0
3 years ago
Okay Adam has 16.45 kg of flour and he use a 6.4 kg to make his Hot Cross Buns the remaining flour is exactly enough to make 15
Karolina [17]
16.45 - 6.4 = 10.05kg of flour to make 15 batches of scones
1 batch = 10.05/15 
= 0.67kg of flour.
6 0
3 years ago
Read 2 more answers
1. Find the value of the expressions using the correct order of operations.
Basile [38]
All the answers to your questions. The ones you did are correct as well

5 0
3 years ago
When fishing off the shores of Florida, a spotted seatrout must be between 10 and 30 inches long before it can be kept; otherwis
Mademuasel [1]

Answer:

There is a 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lengths of the spotted seatrout that are caught, are normally distributed with a mean of 22 inches, and a standard deviation of 4 inches, so \mu = 22, \sigma = 4.

What is the probability that a fisherman catches a spotted seatrout within the legal limits?

They must be between 10 and 30 inches.

So, this is the pvalue of the Z score of X = 30 subtracted by the pvalue of the Z score of X = 10

X = 30

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 22}{4}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 10

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 22}{4}

Z = -3

Z = -3 has a pvalue of 0.00135.

This means that there is a 0.9772-0.00135 = 0.97585 = 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

3 0
3 years ago
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