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castortr0y [4]
4 years ago
15

A mineral is discovered that cleaves in parallel pieces that look like pages from a book?

Chemistry
1 answer:
Dmitrij [34]4 years ago
5 0
The mineral that you described is called Muscovite. The pages of the book description fits muscovite found in granite pegmatites where it is found in large crystals with a pseudohexagonal outline that are called "books".
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Based on the balanced chemical equation for the preparation of malachite, what is the composition of the bubbles formed when sod
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Answer:

Carbon Dioxide = CO2

Explanation:

The synthesis of Malachite is seen in the chemical formula:

CuSO 4 . 5H2O(aq) + 2NaCO3(aq) --> CuCO 3 Cu(OH) 2 (s) + 2Na 2 SO 4 (aq) + CO 2 (g) + 9H 2 O(l)

The bubbles mentioned in the question hints that our interest is the compounds in their gseous phase  (g).

Upon examining the chemical equation, only CO2 is in the gaseous state and hence the only one that can be formed as bubbles,

3 0
3 years ago
Please help! I’ll mark brainliest for best answer!
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Answer:

The Atomic Number

Explanation:

The X would be the Atomic Number or amount of protons sorrounding the nucleus of that atom.

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3 years ago
Plz help thx brainliest btw :)
Marina86 [1]

Answer:

1. earth metal 2. halogen 3.The elements are arranged in seven horizontal rows, called periods or series, and 18 vertical columns, called groups. ... Elements in the periodic table are organized according to their properties.

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3 0
3 years ago
Read 2 more answers
2. A 10.0 g ice cube, initially at 0.0ºC, is melted in 100.0 g of water that was initially 20.0ºC. After the ice has melted, the
arlik [135]

Answer:

The heat lost  by the water  Q_{water}  = 3.8 KJ

The heat gain by ice  Q_{ice} = 228.76 J

The heat required to melt the ice Q_{melt} = 3340 J

Explanation:

Mass of ice cube m_{ice} = 10 gm

Initial temperature of ice cube T_{ice} = 0 °c

Mass of water m_{water} = 100 gm

Initial temperature of water T_{w} = 20 °c

Final temperature of mixture T_{f} = 10.93 °c

(a). Total heat lost by the water Q_{water}  =  m_{water} C_{w} ( T_{f} - T_{w} )

⇒ Q_{water}  = 100 × 4.184 (20 - 10.93)

⇒ Q_{water}  = 3.8 KJ

This is the heat lost  by the water.

(b). Heat gained by the ice cube Q_{ice} = m_{ice} C_{ice} (T_{f} - T_{ice}  )

⇒ Q_{ice} = 10 × 2.093 × ( 10.93 - 0)

⇒ Q_{ice} = 228.76 J

This is the heat gain by ice.

(C). Heat required to melt the ice Q_{melt} = m_{ice} × Latent Heat

⇒ Q_{melt} = 10 × 334

⇒ Q_{melt} = 3340 J

This is the heat required to melt the ice.

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3 years ago
12) Balance the following chemical equation:<br> Zn +<br> H3PO4<br> Zn3(PO4)2 +<br> H2
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Answer:

Sorry I am not very good at chemistry.

Explanation:

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