All categories

3 years ago

What is the mass of a sample containing 8.53×10 to the 24th power formula units of magnesium phosphate?

Chemistry

1 answer:

Archy [21]3 years ago

5 0

Answer:

Mass = 3732.62 g

Explanation:

Given data:

Number of formula units = 8.53×10²⁴

Mass of sample = ?

Solution:

1 mole of any substance contain 6.022×10²³ formula units.

8.53×10²⁴ formula units ×1 mol / 6.022×10²³ formula units

1.42×10¹ mol

14.2 mol

Mass of magnesium phosphate:

Mass = number of moles × molar mass

Mass = 14.2 mol × 262.86 g/mol

Mass = 3732.62 g

You might be interested in

21. For each of the following precipitation reactions,

Phantasy [73]

I would say B.HS(aq)+NiSO4(aq)

6 0

3 years ago

HELP - a solution NaOCl was prepared at pH 10.3. calculate the concentration of the salt formed. Given Ka for HOCl=3.0x10^-8

GenaCL600 [577]

First we dissociate the salt

NaOCl ⇒ Na⁺ + OCl⁻
note that [NaOCl] = [OCl⁻]

note that Na⁺ does not undergo hydrolysis so it is a spectator.
OCl⁻ can reform HOCl in an equilibrium, with OCl⁻ acting as the base.

OCl⁻ + H₂O ⇄ OH⁻ + HOCL

<span>Ka for HOCl = 3.0x10^-8, therefore

Kb for OCL</span>⁻ = Kw / (Ka for HOCl)
                       = 1.0 × 10⁻¹⁴ / 3.0 <span>× 10⁻⁸
                       = 3.3 × 10⁻⁷

</span>since Kb for OCl⁻ is given, and the pH is given, then [OCl⁻] must be found, and [OCl⁻] = [NaOCl]

convert the pH into [OH⁻]:
pOH = 14 - pH = 14 - 10.3 = 3.7
[OH⁻] = 10^(-3.7) = 1.995 × 10⁻⁴

set up equib table

          OCl⁻                + H₂O    ⇄      OH⁻        +       HOCl
ST     x                             0                       0
+Δ    -1.995 × 10⁻⁴               +1.995 × 10⁻⁴        +1.995 × 10⁻⁴
---------------------------------------------------------------------------------
EQ: x -1.995 × 10⁻⁴         1.995 × 10⁻⁴          1.995 × 10⁻⁴

Kb = [OH⁻][HOCl] / [OCl⁻]
3.3 × 10⁻⁷ = (1.995 × 10⁻⁴)² / (x -1.995 × 10⁻⁴ )
x = 1.1963 × 10⁻¹ M = [OCl⁻] = [NaOCl]

The concentration of the salt formed, <span>NaOCl,</span> is 1.2 × 10⁻¹ M

7 0

4 years ago

Okay this is the only way to get my answers

cupoosta [38]

Answer:

Your answer is Answer thank me later :) <3

Explanation:

7 0

2 years ago

Which equivalence factor should you use to convert from 3.48 x 1018 atoms of magnesium (Mg) to moles of magnesium?

attashe74 [19]

You should divide by 6.02*10^23.

5 0

3 years ago

Enthalpies of reaction calculated from bond energies and from enthalpies of formation are often, but not always, close to each o

jolli1 [7]

The enthalpy change in a reaction is given by-

ΔH°rxn = ∑nΔH°f,products - ∑nΔH°f,reactants

This can be expressed in terms of bond energy as-

ΔH°rxn = BEreactants - BEproducts

Therefore, the calculated bond energy according to the above equation will be-

ΔH°rxn = [ (C-C) + 2(C-O) + 4(C-H) + 2(O-H) ] - [ (C-C) + 2(C-O) + 4(C-H) + 2(O-H) = 0 kJ/mol

<h3>What is enthalpy change?</h3>

Enthalpy change is a measure of the energy emitted or consumed in a reaction. This can be determined using the following equation which involves standard enthalpy of reactant and product formation:

ΔH°rxn = ∑nΔH°f,products - ∑nΔH°f,reactants

<h3>What is bond energy?</h3>

Bond energy is defined as the amount of energy needed to dissociate a mole of molecules into their individual atoms.

Learn more about the Enthalpy Change here:

brainly.com/question/14047927

#SPJ4

6 0

2 years ago

What is the mass of a sample containing 8.53×10 to the 24th power formula units of magnesium phosphate?￼

What is the mass of a sample containing 8.53×10 to the 24th power formula units of magnesium phosphate?