The <span>henderson-hasselbalck equation is this
pH = pK + log [salt]/[acid]
We are given with
pH = 4.00
</span><span>1.50 l of 0.0200 m solution of benzoic acid
The pK for benzoic acid is
4.20
Solving for the moles of salt,
4 = 4.2 + log 1.5(0.02)/n
n = 71.62 moles
The mass is
m = 71.62 (249.2)
m = 17800 grams</span>
Answer:
H₂O.
Explanation:
- It is clear from the balanced equation:
<em>CH₄ + 2H₂O → CO₂ + 4H₂.</em>
that 1.0 mole of CH₄ reacts with 2.0 moles of H₂O to produce 1.0 mole of CO₂ and 4.0 moles of H₂.
- To determine the limiting reactant, we should calculate the no. of moles of (20 g) CH₄ and (15 g) H₂O using the relation:
<em>n = mass/molar mass</em>
<em></em>
no. of moles of CH₄ = mass/molar mass = (20 g)/(16 g/mol) = 1.25 mol.
no. of moles of H₂O = mass/molar mass = (15 g)/(18 g/mol) = 0.833 mol.
- <em>from the balanced reaction, 1.0 mole of CH₄ reacts with 2.0 moles of H₂O.</em>
So, from the calculated no. of moles: 0.4167 mole of CH₄ reacts completely with 0.833 mole of H₂O and the remaining of CH₄ will be in excess.
<u><em>So, the limiting reactant is H₂O.</em></u>
Answer:
<h2>7.65 litres </h2>
Explanation:
The new volume can be found by using the formula for Boyle's law which is
Since we're finding the new volume
15 kPa = 15,000 Pa
50 kPa = 50,000 Pa
We have
We have the final answer as
<h3>7.65 litres </h3>
Hope this helps you
Answer:
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Explanation:
Neutral solution, hope this helps :)
