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RSB [31]
3 years ago
7

According to the ideal gas law, what happens to the volume of a gas when the temperature doubles(all else held constant)

Chemistry
2 answers:
TiliK225 [7]3 years ago
7 0

Answer:

The volume will double too

Explanation:

The ideal gas law is the following:

PV = nRT

Now, in order to know what happens to the volume of a gas if temperature is doubled, let's write an expression for temperature for both conditions:

T1 = PV1/nR

T2 = PV2/nR

We know that Temperature is being duplicated so T2 = 2T1. Replacing in the expression we have:

2T1 = PV2/nR

Replacing T1 here we have:

2PV1/nR = PV2/nR

In this expression, P, n and R cancels out, because they remain constant so, all we have left is:

<em>2V1 = V2</em>

<em>This means that if we double the temperature, the volume will double too and they directly proportional to pressure and temperature.</em>

Rudiy273 years ago
3 0
If the temperature doubles, then the volume of the gas also doubles because temperature is proportional to volume according to the ideal gas law. Hope this helps. 
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Question 1 how many moles of helium are found in a balloon that contains 5.5 l of helium at a pressure of 1.15 atm and a tempera
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Using pv=nRT
T= 22+273 K
P=1.15 Pa
R=8.31
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8. True or False: There are some exceptions to the rule.... organisms such as a protist called a
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There are some exceptions to the rule organisms such as a protist called a  euglena can be both heterotrophic and autotrophic. This is a true statement.

Explanation:

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Every ribosome has three tRNA binding sites: the A site, the P site, and the E site. For the given sentences, select the correct
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A. All sites B. A site C. E site D. P site

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A. Because all sites consequently take place while peptide is synthesized.

B. A site (aminoacyl site) is called so because it binds to charged aminoacyl peptide.

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5K + KNO3 ------ 3K2O + N
masya89 [10]

Answer:

174,957.143 grams of potassium and 89,228.478 grams of potassium nitrate will be needed.

Explanation:

5K +KNO_3\rightarrow 3K_2O + N

Mass of nitrogen =  27 lbs = 12,247 g

1 lbs = 453.592 g

Moles of nitrogen = \frac{12,247 g}{14 g/mol}=874.786 mol

According to reaction, 1 mole of nitrogen is produced from 5 moles of potassium and 1 mole of potassium nitrate.

Then 874.786 mol of nitrogen will be obtained from :

\frac{5}{1}\times 874.786 mol=4,373.928 mol of potassium.

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Mass of 4,373.928 moles of potassium:

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Mass of 874.789 moles of potassium nitrate:

874.789 mol\times 102 g/mol=89,228.478 g of potassium nitrate

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