The balanced reaction is
3Na3PO4 + 2CuSO4 ------> 3Na2SO4 + Cu3(PO4)2
To balance this reaction of double displacement, we see first that this reaction maintain the valence numbers of every atom.
Then, to have the same value of Na in the two sides of the reaction we multiply for the number of the other side. So,
(Na3PO4)x 2
(Na2SO4)x3
As we can see either, we need to balance PO4 cause there are two molecules of this in the reactant side, so we have two molecules of PO4 in the product either.
Then we get
3Na3PO4 + 2CuSO4 ------> 3Na2SO4 + Cu3(PO4)2
To probe that balance was correct, you can verify that the charges are exactly the opposite.
The case is acidic since calculated pH is below 7 that is 2.3
The hydroxide and hydrogen ion levels in a solution are the sources for calculating pOH and pH levels, respectively, and are the basis of whether a solution is acidic or basic
[H₃O+]=5.3×10⁻³M
To determine the hydroxide ion concentration, we use:
[OH−][H3O+]=1×10⁻¹⁴
We isolate the hydroxide ion concentration:
[OH−]=1×10−145.3×10⁻³M
Solving this, we obtain:
[OH−]=1.9×10−¹²M
We can determine whether the solution is acidic or basic by calculating the pH level:
pH=−log[H3O+]
We substitute in the hydronium ion concentration given:
pH=−Log(5.3×10−3)pH=2.3
Since the pH is below 7, the solution is acidic
Learn more about hydroxide ion here-
brainly.com/question/25883474
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It's just H20 but with 3 water molecules
