We know that the points at which the parabola intersects the x axis are
(-5,0) and (1,0)
So the extent between these two points would be the base of the triangle
lets find the length of the base using the distance formula
![\sqrt{[(-5-1)^{2}+(0-0)^{2} ]}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%5B%28-5-1%29%5E%7B2%7D%2B%280-0%29%5E%7B2%7D%20%5D%7D%20%20)
the base b=6
We will get the height of the triangle when we put x=0 in the equation
y=a(0+5)(0-1)
y=-5a
so height = -5a (we take +5a since it is the height)
We know that the area of the triangle =
× 6 × (5a) = 12
15a=12
a= 
I believe the answer is 8
Answer:
same
Step-by-step explanation:
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Add whole numbers: 2 + 6 + 8 = 16
Add fractions:
= 1/3 + 3/4 + 1/2
= (8 + 18 + 12) ÷ 24
= 38/24 or 1 14/24 or simplified to 1 7/12
Total surface area = 16 + 1 7/12 or 17 7/12