of course, you can always use (x-1)(x-1)(2x+1)(x²-4x+5) as well.
Can someone help me please
1 answer:
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of course, you can always use (x-1)(x-1)(2x+1)(x²-4x+5) as well.
Answer:
Diverges
Step-by-step explanation:
For the improper integral to converge the limit must exist, if the limit does not exist or is infinite the integral diverges;
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Where a and be is infinity
The solution of this is infinity and therefore the integral diverges because the first expression is undefined because ∞/∞, the second term is 4·∞ which is infinity and infinity added to any number is infinity