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Rudiy27
3 years ago
9

Can someone help me please

Mathematics
1 answer:
egoroff_w [7]3 years ago
8 0

Answer:

8)449.1 9)349.3

Step-by-step explanation:

8.499+10/100*499=499+0.1*499=499+49.9=548.9

9.499-30/100*499=499-0.3*499=499-149.7=349.3

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Marianna [84]
\bf \begin{cases}
x=1\implies &x-1=0\\
x=1\implies &x-1=0\\
x=-\frac{1}{2}\implies 2x=-1\implies &2x+1=0\\
x=2+i\implies &x-2-i=0\\
x=2-i\implies &x-2+i=0
\end{cases}
\\\\\\
(x-1)(x-1)(2x+1)(x-2-i)(x-2+i)=\stackrel{original~polynomial}{0}
\\\\\\
(x-1)^2(2x+1)~\stackrel{\textit{difference of squares}}{[(x-2)-(i)][(x-2)+(i)]}

\bf (x^2-2x+1)(2x+1)~[(x-2)^2-(i)^2]
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(x^2-2x+1)(2x+1)~[(x^2-4x+4)-(-1)]
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(x^2-2x+1)(2x+1)~[(x^2-4x+4)+1]
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(x^2-2x+1)(2x+1)~[x^2-4x+5]
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(x^2-2x+1)(2x+1)(x^2-4x+5)

of course, you can always use  (x-1)(x-1)(2x+1)(x²-4x+5)  as well.
7 0
3 years ago
1. Find the value of x. *
oksano4ka [1.4K]
Forgive me if I’m wrong. 25?
4 0
3 years ago
Read 2 more answers
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IRINA_888 [86]

Answer:

15

Step-by-step explanation:

Hoped it helped

3 0
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Step-by-step explanation:

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kiruha [24]

Answer:

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Step-by-step explanation:

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