Answer:
rational
Step-by-step explanation:
Because if you take the square root of 4 you get 2
if it was irrational then it would be a decimal or fraction
(plz mark braillist)
Ok, so you are given the value of P=q+2
The substitution method tells us that we must insert the value we know, into the second equation, 4P+3q= -27
Doing so will give us 4(q+2)+3q= -27
For right now, lets just focus on the first part, 4(q+2)
We can simplify this by distributing(multiplying) the 4 to whats inside the variables.
This will give us 4q+8
now lets add this back to the rest of the equation >>> 4q+8+3q = -27
We can further simplify by adding like terms >>> 7q+8 = -27
subtract the 8 from both sides >>> 7q = -35
now divide both sides by 7 >>> q = -35/7
Therefor q = -5
EDIT*
now that we know q = -5 we can put q into the equation for P !
we know that p=q+2
so lets put q in now >>> p=(-5)+2
and simplify>>> p = -3
I hope this helps:)
Answer:
x = 5
Step-by-step explanation:
sin theta = opposite side / hypotenuse
sin 53 = 4/x
Multiply each side by x
x sin 53 = 4/x *x
x sin 53 = 4
Divide each side by sin 53
x sin 53 / sin 53 = 4 / sin 53
x = 4 /sin 53
x = 5.008542633
To the nearest whole number
x = 5
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
Learn more about computations on:
brainly.com/question/4658834
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
y" = csc(x)[9cot²(x) - csc²(x)]
Step-by-step explanation:
Step 1: Define
y = 9csc(x)
Step 2: Find 1st derivative
y' = -9csc(x)cot(x)
Step 3: Find 2nd derivative
y" = 9csc(x)cot(x)cot(x) + -csc(x)csc²(x)
y" = 9csc(x)cot²(x) - csc³(x)
y" = csc(x)[9cot²(x) - csc²(x)]
