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PIT_PIT [208]
3 years ago
14

14. Which of the following statements is incorrect?

Mathematics
1 answer:
Reptile [31]3 years ago
7 0

Answer:

D is incorrect this is your answer

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Giving brainliest, thanks, rating answer, and friending on Brianly profile immediately!
Stolb23 [73]

Answer:

The answer is 3054.8

Step-by-step explanation:

V = 4/3 × 22/7 × 9 × 9 × 9

V = 4 × 22/7 × 3 × 81

V = 4 × 22 × 243/7

V = 21384/7

V = 3054.8

Thus, The answer is 3054.8

7 0
2 years ago
Read 2 more answers
HELP!!!!!
bogdanovich [222]

Answer:

It’s D

Step-by-step explanation:

6 0
3 years ago
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Simplify. Rewrite the expression in the form b^n. b^10/b^6
Vlad1618 [11]

Answer:

<h2>The answer is b⁴</h2>

Step-by-step explanation:

\frac{ {b}^{10} }{ {b}^{6} }

Using the rules of indices

That's

\frac{ {a}^{x} }{ {a}^{y} }  =  {a}^{x - y}

Since the bases are the same and are dividing we subtract the exponents

So we have

\frac{ {b}^{10} }{ {b}^{6} }  =  {b}^{10 - 6}

We have the final answer as

<h2>b⁴</h2>

Hope this helps you

6 0
3 years ago
Read 2 more answers
(x+1)(2x-4)(1/x+1) = (x+1)(2x-4)(1-5/2x-4)
Sunny_sXe [5.5K]

Solution:

(x+1)(2x-4)(\frac{1}{x}+1)=(x+1)(2x-4)(1-\frac{5}{2x}-4)\\(x+1)(2x-4)(\frac{1}{x}+1)-(x+1)(2x-4)(1-\frac{5}{2x}-4) = 0\\(x+1)(2x-4)(\frac{1}{x}+1-(1-\frac{5}{2x}-4))=0\\(x+1)(2x-4)(\frac{1}{x}+1-(-3\frac{5}{2x}))=0\\(x+1)(2x-4)(\frac{1}{x}+1+3+\frac{5}{2x})=0\\(x+1)(2x-4)(\frac{1}{x}+4+\frac{5}{2x})=0\\(x+1)(2x-4)(\frac{5x^{2}+8x+2}{2x} )=0\\

x+1=0\\x=-1\\\\2x-4=0\\x=2\\\\\frac{5x^{2}+8x+2}{2x}=0\\x=\frac{-4+\sqrt[]{6}}{5}\\x=\frac{-4-\sqrt[]{6}}{5}

Answer:

x=-1\\x=2\\x=\frac{-4+\sqrt[]{6}}{5}\\x=\frac{-4-\sqrt[]{6}}{5}

<em>Hope this was helpful.</em>

8 0
3 years ago
Will select brainliest if ur answer is correct
ella [17]

Answer:

B (I think)

Step-by-step explanation:

A function can't have two X values that are the same (If I remember correctly) and the second table is the only one that doesn't have duplicated X values

6 0
3 years ago
Read 2 more answers
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