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Alina [70]
3 years ago
12

A delivery truck is transporting boxes of two sizes: large and small. The large boxes weigh 50 pounds each, and the small boxes

weigh 20 pounds each. There are 120 boxes in all. If the truck is carrying a total of 4050 pounds in boxes, how many of each type of box is it carrying?
Mathematics
1 answer:
skad [1K]3 years ago
6 0
So this is how we are going to solve for the given problem above.
Given that x = number of large boxes
and 120-x = number of small boxes.
So here is the solution:
50x + (120-x)20 = 4050
50x + 2400 - 20x = 4050
30x + 2400 = 4050
30x = 4050 - 2400
30x = 1650 <<divide both sides by 30
x = 55.
Therefore, there are 55 large boxes
120 - x = small boxes
120 - 55 = 65 small boxes.
Hope this is the answer that you are looking for.
Let me know if you need more help next time!

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coldgirl [10]

Answer:

a = 9, b = 3, c = 0

Step-by-step explanation:

f(x) = (1/3)^x

a = f(-2) = (1/3)^-2= 9

b = f(-1) = (1/3)^-1 = 3

c = f(0) = (1/3)^0 = 1

whenever something is to the power of 0, the answer will always be 1

6 0
3 years ago
Two sisters, sister A and sister B, play SCRABBLE with each other every evening. Sister A is a statistician, and she draws a ran
snow_tiger [21]

Answer:

First question: LCL = 522, UCL = 1000.5

Second question: A sample size no smaller than 418 is needed.

Step-by-step explanation:

First question:

Lower bound:

0.36 of 1450. So

0.36*1450 = 522

Upper bound:

0.69 of 1450. So

0.69*1450 = 1000.5

LCL = 522, UCL = 1000.5

Second question:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The project manager believes that p will turn out to be approximately 0.11.

This means that \pi = 0.11

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The project manager wants to estimate the proportion to within 0.03

This means that the sample size needed is given by n, and n is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.11*0.89}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.11*0.89}

\sqrt{n} = \frac{1.96\sqrt{0.11*0.89}}{0.03}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.11*0.89}}{0.03})^2

n = 417.9

Rounding up

A sample size no smaller than 418 is needed.

6 0
3 years ago
2/4, find the surface area
Oduvanchick [21]

Answer:

144 un^2

Step-by-step explanation:

Base: 4 × 11 = 44

Left-most face: 3 × 11 = 33

Top face: 5 × 11 = 55

Triangular faces: 3 × 4 = 12

Add: 44 + 33 + 55 + 12 = 144

7 0
4 years ago
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slamgirl [31]
Quotient: 7
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4 0
3 years ago
Read 2 more answers
Directed line segment PT has endpoints whose
crimeas [40]

Answer:

(2 , 5)

Step-by-step explanation:

point (x,y) that divides the segment   PI in the ratio 2 to 1

PD=4 - (-2) = 6     PE/ED=2/1     PE=2ED      PE+ED=6    3ED=6    ED=2   PE=4

coordinate of E (2,1)   .... 2 is x coordinate of E

DI=7-1=6    DF/FI=2/1     DF=4

coordinate of F (4,5)   .... .... 5 is y coordinate of E

CF // PD            PC/CI=DF/FI=2/1

C (2,5)

4 0
3 years ago
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