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Alina [70]
3 years ago
12

A delivery truck is transporting boxes of two sizes: large and small. The large boxes weigh 50 pounds each, and the small boxes

weigh 20 pounds each. There are 120 boxes in all. If the truck is carrying a total of 4050 pounds in boxes, how many of each type of box is it carrying?
Mathematics
1 answer:
skad [1K]3 years ago
6 0
So this is how we are going to solve for the given problem above.
Given that x = number of large boxes
and 120-x = number of small boxes.
So here is the solution:
50x + (120-x)20 = 4050
50x + 2400 - 20x = 4050
30x + 2400 = 4050
30x = 4050 - 2400
30x = 1650 <<divide both sides by 30
x = 55.
Therefore, there are 55 large boxes
120 - x = small boxes
120 - 55 = 65 small boxes.
Hope this is the answer that you are looking for.
Let me know if you need more help next time!

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Answer:

CD = two square root of 10 end square root

Step-by-step explanation:

To find the length of a segment, use the distance formula. Substitute the order pairs for the endpoints of the segment. CD has the end points (-7, -4) and (-1, -2).

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Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3 5 , KE = 8, LM KN = 3 5 Find: KM, LM, KN, Area of KLMN
prisoha [69]
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the 
KM² = KE² + ME²KM² = 8² + (3√5)²       = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N  Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the  formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM)          = 1/2 * 3√5 * (40 + 24)         = 1/2 * 3√5 * 64         = 3 x 2.23 * 32         = 214.66 units²
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2.The side opposite the right angle is called the hypotenuse (side c in the figure).

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