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yarga [219]
3 years ago
12

A briefcase has a three-digit lock code that does not include zero as a digit.

Mathematics
2 answers:
Strike441 [17]3 years ago
6 0

The correct answer is:

A. 24 out of 504.

The probability that the lock code consists of all even digits is 24 out of 504, if the same digit is not used more than once in the lock code.

|Huntrw6|

Sladkaya [172]3 years ago
4 0
First it can be a 2,4,6,8. Four numbers.
Then one is removed, leaving three numbers.
Then one is removed, leaving two numbers.
Possibilities for that to happen: 4*3*2 = 24.
Total amount of possibilities: 9*8*7 = 504.
So the answer is A: 24 out of 504.
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Solve the inequality 2(m-3)+7<21
choli [55]
Hey! So, the answer is the letter B.

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3 years ago
40 points. Factor the following polynomial.
madam [21]

Answer:

A

Step-by-step explanation:

49y² - x² ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

49y² - x²

= (7y)² - x²

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2 years ago
Halp Exam <br><br> Converting a decimal to a proper fraction in simplest form: Advanced
jeyben [28]

Answer:

0.37 as a fraction is 37/100

Step-by-step explanation:

Because

7 0
2 years ago
WHOEVER ANSWERS IT'S FIRST GETS THE BRAINLIEST!!!! PLEASE HELP!!
Virty [35]
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Calculate the number of hours:

24 x 3 = 72

72/13 = 5.5....

This is 5 whole half lives

You have to half the value 5 times

149/2 = 74.5

74.5/2 = 37.25

37.25/2 = 18.625

18.625/2 = 9.3125

9.3125/2 = 4.65625

The closest value is B. 3.21 so that should be the answer

<h3><u>✽</u></h3>

➶ Hope This Helps You!

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8 0
3 years ago
A researcher obtains t = 2.35 for a repeated-measures study using a sample of n = 8 participants. Based on this t value, what is
ZanzabumX [31]

Answer:

p_v =2*P(t_{7}>2.35)=2*0.0255=0.051  

If we compare the p value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% or 1% of significance we fail to reject the null hypothesis.

Step-by-step explanation:

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level is not provided but we can assume it as \alpha=0.05. First we need to calculate the degrees of freedom like this:

df=n-1=8-1=7

The next step would be calculate the p value for this test.  Since is a bilateral test or two tailed test, the p value would be:  

p_v =2*P(t_{7}>2.35)=2*0.0255=0.051  

If we compare the p value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% or 1% of significance we fail to reject the null hypothesis.  

5 0
3 years ago
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