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2 years ago

What graph shows a proportional relationship between x and y?

Mathematics

2 answers:

Kazeer [188]2 years ago

7 0

I believe it would have to be the second graph as a proportional relationship has to make a straight line that passes through the origin

horrorfan [7]2 years ago

5 0

Answer:

second graph

Step-by-step explanation:

the line running at same rate

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Kelly spends $63.90 on items for a party. She buys thank you cards that cost $5.40 (including tax). She also buys gift bags that

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$63.90 (total)

$5.40 (cards)

$11.70/per (bags)

$63.90 - $5.40 = $58.50

$58.50 / $11.70 = 5

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Its 1.33 because you round up if its 5 or greater

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Answer:

i think it's 10.6

Step-by-step explanation:

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3 years ago

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Answer:

$Range=14$

$\sigma^2 =32.4$

$\sigma = 5 .7$

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

$Data: 136, 129, 141, 139, 138, 127$

Solving (a): The range

This is calculated as:

$Range = Highest - Least$

Where:

$Highest = 141; Least = 127$

So:

$Range=141-127$

$Range=14$

Solving (b): The variance

First, we calculate the mean

$\bar x = \frac{1}{n} \sum x$

$\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)$

$\bar x = \frac{1}{6} *810$

$\bar x = 135$

The variance is calculated as:

$\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2$

So, we have:

$\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]$

$\sigma^2 =\frac{1}{5}*[162]$

$\sigma^2 =32.4$

Solving (c): The standard deviation

This is calculated as:

$\sigma = \sqrt {\sigma^2 }$

$\sigma = \sqrt {32.4}$

$\sigma = 5 .7$ --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

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3 years ago

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