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Rzqust [24]
2 years ago
10

What graph shows a proportional relationship between x and y?

Mathematics
2 answers:
Kazeer [188]2 years ago
7 0
I believe it would have to be the second graph as a proportional relationship has to make a straight line that passes through the origin
horrorfan [7]2 years ago
5 0

Answer:

second graph

Step-by-step explanation:

the line running at same rate

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Calculus 3 chapter 16​
o-na [289]

Evaluate \vec F at \vec r :

\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k

Compute the line element d\vec r :

d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt

Simplifying the integrand, we have

\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt

Then the line integral evaluates to

\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}

3 0
1 year ago
I need to find the equal expression to -m(2m+2n)+3mn+2m². Help please?
spin [16.1K]

m(2m+2n)+3mn+2m^2\implies \stackrel{\textit{distributing}}{2m^2+2mn}+3mn+2m^2 \\\\\\ 2m^2+2m^2+2mn+3mn\implies \stackrel{\textit{adding like-terms}}{4m^2+5mn}

4 0
3 years ago
Angle of depression from point a to point c
Arisa [49]

Answer:

32°

Step-by-step explanation:

90 - 58 = 32

4 0
2 years ago
What is the value of this expression when 5a=20?
natita [175]
A=4 

Just divide 5 on both sides :-)
3 0
3 years ago
Read 2 more answers
Suppose f(x)=4x-2 and g(x)=-2x+1
choli [55]
In order to get g(x) you would multiply the equation of f(x) by -1/2.
4x(-1/2)=-2x and -2(-1/2)=1.
3 0
2 years ago
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