Answer:
The answer is below
Step-by-step explanation:
1)
mean (μ) = 12, SD(σ) = 2.3, sample size (n) = 65
Given that the confidence level (c) = 90% = 0.9
α = 1 - c = 0.1
α/2 = 0.05
The z score of α/2 is the same as the z score of 0.45 (0.5 - 0.05) which is equal to 1.65
The margin of error (E) is given as:
The confidence interval = μ ± E = 12 ± 0.47 = (11.53, 12.47)
2)
mean (μ) = 23, SD(σ) = 12, sample size (n) = 45
Given that the confidence level (c) = 88% = 0.88
α = 1 - c = 0.12
α/2 = 0.06
The z score of α/2 is the same as the z score of 0.44 (0.5 - 0.06) which is equal to 1.56
The margin of error (E) is given as:
The confidence interval = μ ± E = 23 ± 2.8 = (22.2, 25.8)
7. y = 1, AB = 1, BD = 10 and AD = 11
8. x = 5, AB = 20 and BC = 20
9. x= 5 and AB = 33
10. No, because AC = 12.5 while AB + BC = 20 (they should equal the same and they don't.)
Three values that would make this true:
5
4
3
Answer:
16 cups of flour
Step-by-step explanation:
Answer:
6.9%.
Step-by-step explanation:
Given that a university class has 26 students: 12 are art majors, 9 are history majors, 5 and are nursing majors, and the professor is planning to select two of the students for a demonstration, where the first student will be selected at random, and then the second student will be selected at random from the remaining students, to determine what is the probability that the first student selected is a history major and the second student is a nursing major the following calculations must be performed:
26 = 100
9 = X
9 x 100/26 = X
900/26 = X
34.61 = X
25 = 100
5 = X
500/25 = X
20 = X
0.2 x 0.3461 = X
0.069 = X
Thus, the probability that the first student selected is a history major and the second student is a nursing major is 6.9%.
