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GrogVix [38]
3 years ago
13

Round of 248,682 to the nearest hundred

Mathematics
2 answers:
zaharov [31]3 years ago
8 0

248,700

682 is closer to 700 than to 600

notka56 [123]3 years ago
5 0

248,682 rounded to nearest hundred means just look at the hundreds place which is the 6. Now the number to the right of that is the 8 and that is the number that helps you decide to round up or down. If it is 4 or lower, keep the hundreds place the same. If it is 5 or higher then round up 1. Then any number that follows the hundreds place all change to 0.

248,700

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i guess Bis the answer bcuz, A sample space is a collection or a set of possible outcomes of a random experiment

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Laura family is going on a vacation they will drive 4,180 miles over the next two weeks about how many miles will they drive an
goldfiish [28.3K]
2090 per week since 4180/2 is 2090
6 0
4 years ago
Which of the following is a solution of x^2 - 7x = -5
Oduvanchick [21]

Answer: B) 7 + or - the square root of 29 all over 2

Which of the following is a solution of x^2 - 7x = -5

A) 7 + or - the square root of 69 all over 2

B) 7 + or - the square root of 29 all over 2

C) -7 + or - the square root of 29 all over 2

D) -7 + or - the square root of 69 all over 2

Step-by-step explanation:

I just did the assignment and the correct answer is B) 7 + or - the square root of 29 all over 2! Hope this helps.

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6 0
3 years ago
Lowering powers write in terms of first power of cosine. Cos^6
yaroslaw [1]

The main identity you need is the double angle one for cosine:

\cos^2x=\dfrac{1+\cos2x}2

We get

\cos^6x=(\cos^2x)^3=\left(\dfrac{1+\cos2x}2\right)^3=\dfrac{(1+\cos2x)^3}8

Expand the numerator to apply the identity again:

\cos^6x=\dfrac{1+3\cos2x+3\cos^22x+\cos^32x}8

\cos^6x=\dfrac{1+3\cos2x+3\left(\frac{1+\cos2(2x)}2\right)+\cos2x\left(\frac{1+\cos2(2x)}2\right)}8

\cos^6x=\dfrac{1+3\cos2x+\frac32+\frac32\cos4x+\frac12\cos2x(1+\cos4x)}8

\cos^6x=\dfrac5{16}+\dfrac7{16}\cos2x+\dfrac3{16}\cos4x+\dfrac1{16}\cos2x\cos4x

Finally, make use of the product identity for cosine:

\cos2x\cos4x=\dfrac{\cos6x+\cos2x}2

so that ultimately,

\cos^6x=\dfrac5{16}+\dfrac7{16}\cos2x+\dfrac3{16}\cos4x+\dfrac1{32}\cos2x+\dfrac1{32}\cos6x

\cos^6x=\dfrac5{16}+\dfrac{15}{32}\cos2x+\dfrac3{16}\cos4x+\dfrac1{32}\cos6x

4 0
4 years ago
Which is the correct form
lesya [120]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
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