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koban [17]
3 years ago
15

What is the quotient of the complex number 4-3i divided by its conjugate ?

Mathematics
2 answers:
sashaice [31]3 years ago
4 0

Answer:

7/25 - 24/25i

Step-by-step explanation:

mina [271]3 years ago
3 0

Answer:

Quotient is\frac{7-24i}{25}

Step-by-step explanation:

Given is a complex number as 4-3i

We have to find the quotient when divided by its conjugate

Its conjugate is

4+3i

When divided we have

\frac{4-3i}{4+3i} =\frac{4-3i}{4+3i} \frac{4-3i}{4-3i}

(to simplify the above)

=\frac{(4-3i)^2}{4^2+3^2} \\=\frac{7-24i}{25}

Quotient is \frac{7-24i}{25}

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Answer:

the vertex is ( 3 , 3)

Symetric axis‘s equation: x = 3

Step-by-step explanation:

Let‘s name the function ” f ”

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the vertex has coordinates of ( -b/2a , f(-b/2a) )

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Answer:

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Don't worry, I got you. Also, my calculator does too.

We set h equal to 27, because we want the height to be 27 when we solve for t.

That leaves us with:

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Using quadratic, you get

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