All categories

2 years ago

3m-10 when m= -3 pls explain

Mathematics

2 answers:

marshall27 [118]2 years ago

5 0

Hi there!

$\large\boxed{-19}$

3m - 10

Find m = -3

Substitute -3 for "m":

3(-3) - 10

-9 - 10 = -19

Elena-2011 [213]2 years ago

3 0

Answer:

- 19

Step-by-step explanation:

Step 1:

3m - 10 Equation

Step 2:

3 ( - 3 ) - 10 Substitute - 3 for m

Step 3:

- 9 - 10 Multiply

Answer:

- 19 Subtract

Hope This Helps :)

You might be interested in

It takes Mia 1/4 hour to pick out all beads and 1/10 hour to string them. If she only has 5 and 1/4 to make bracelets how many w

JulsSmile [24]

Answer:

Step-by-step explanation:

Mia take 1/4 and 1/10 hours to create a bracelet. This is 1/4 + 1/10 = 10/40 + 4/40 = 14/40 = 7/20.

It takes her a total of 7/20 hours to make the bracelet. She has 5 1/4 hours to work. To find the number of bracelets she can make divide 5 1/4 by 7/20.

Write first 5 1/4 as a mixed number. 21/4. Then rewrite it as multiplication with the reciprocal of 7/20 to divide fractions.

21/4 * 20/7 = 420/28 = 15

She will make 15 bracelets.

4 0

2 years ago

The domain of both

Margarita [4]

Answer:

The domain of function $h(x)$ is set of all real numbers.

Domain: (-∞,∞)

Step-by-step explanation:

Given:

$f(x)=x-6$

$g(x)=x+6$

the domain of both the above functions is all real number.

To find domain of :

$h(x)=f(x)g(x)$

Substituting functions $f(x)$ and $g(x)$ to find $h(x)$

$h(x)=(x-6)(x+6)$

The product can be written as difference of squares. $[a^2-b^2=(a+b)(a-b)]$

∴ $h(x)=x^2-36$

The degree of the function $h(x)$ is 2 as the exponent of leading term $x^2$ is 2. Thus its a quadratic equation.

For any quadratic equation the domain is set of all real numbers.

So Domain of $h(x)$ is (-∞,∞)

7 0

2 years ago

Find the x-intercepts of the parabola with vertex (1, -9) and y intercept at (0, -6).

Sergio [31]

Hello,

Equation is y=k(x-1)²-9
and when x=0,y=-6==>-6=k*1²-9==>k=3

y=3(x-1)²-9
when y=0, 3(x-1)²-9=0
==>(x-1-√3)(x-1+√3)=0
x-intercepts are (1+√3,0) and (1-√3,0)

Answer B.

3 0

2 years ago

F(x) =5x^2-20x+3 how to find minimum

Leya [2.2K]

Answer:

(2,-17) should be the minimum.

Step-by-step explanation:

The minimum of a quadratic function occurs at $x=-\frac{b}{2a}$ . If a is positive, the minimum value of the function is $f(-\frac{b}{2a})$

$f_{min}x=ax^2+bx+c$ occurs at $x=-\frac{b}{2a}$

Find the value of $x=-\frac{b}{2a}$

x = 2

evaluate f(2).

replace the variable x with 2 in the expression.

$f(2)=5(2)^2-20(2)+3$

simplify the result.

$f(2)=5(4)-20(2)+3$

$f(2)=20-40+3$

$f(2)=-17$

The final answer is -17

Use the x and y values to find where the minimum occurs.

HOPE THIS HELPS!

3 0

2 years ago

Let u = (1, 2 -2), v= (2, 1, 3) and w = j + 4k. a) Find cos theta, where theta is the angle in degrees between u and w.

vodka [1.7K]

Answer: The value of cos theta is -0.352.

Step-by-step explanation:

Since we have given that

$\vec{u}=1\hat{i}+2\hat{j}-2\hat{k}\and\\\\\vec{w}=\hat{j}+4\hat{k}$

We need to find the cos theta between u and w.

As we know the formula for angle between two vectors.

$\cos\ \theta=\dfrac{\vec{u}.\vec{w}}{\mid u\mid \mid w\mid}$

So, it becomes,

$\cos \theta=\dfrac{2-8}{\sqrt{1^2+2^2+(-2)^2}\sqrt{1^2+4^2}}\\\\\cos \theta=\dfrac{-6}{\sqrt{17}\sqrt{17}}=\dfrac{-6}{17}=-0.352\\\\\theta=\cos^{-1}(\dfrac{-6}{17})=110.66^\circ$

Hence, the value of cos theta is -0.352.

8 0

2 years ago