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3 years ago

Someone pls help me I need this to get math grade up

Mathematics

1 answer:

nexus9112 [7]3 years ago

8 0

9514 1404 393

Answer:

see attached

Step-by-step explanation:

Dilation by a factor of 3 about point P moves A to a position that is 3 times as far from P. This is shown in the attachment.

Dilation is always along a line through the original point and the center of dilation.

(The lines are there in the attachment simply to show you that the image position is 3 times the distance from P that the original position is. They are not part of the dilation or the image.)

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Can someone help me with this ASAP

Vika [28.1K]

Answer:

1.4 is the slope

Step-by-step explanation:

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3 0

2 years ago

The population of deer in a national forest has been increasing by about 5.8% annually. The current population is about 2,200 de

arsen [322]

Answer:

127 goes in the box

Step-by-step explanation:

I hope this helps you.

8 0

2 years ago

there were 20 plants sold at a store on Saturday and 30 plants sold at the store on Sunday. customers bought 5 plants each. how

pshichka [43]

Answer:

Step-by-step explanation:

20/5 = 4 customers bought plants on Saturday; 30/5 = 6 customers bought plants on Sunday. In all 4 + 6 = 10 customers bought the plants.

6 0

3 years ago

Find the number set which satisfies each of the problems. If 20 is added to the number, the absolute value of the result is 6.

victus00 [196]

Answer: {-14,-26}

Step-by-step explanation:

Let x be the number.

Given statements: If 20 is added to the number, the absolute value of the result is 6.

i.e. |x+20| =6

Since $|y|=c \Rightarrow y= c \text{ or } y = -c$

So, $|x+20| =6\Rightarrow\ x+20=6\text{ or }x+20=-6$

$\Rightarrow\ x= 6-20\text{ or } x= -6-20\\\\\Rightarrow\ x=-14\text{ or } x=-26$

hence, set of values of x = {-14,-26}

7 0

3 years ago

In this problem, y = c1ex + c2eâx is a two-parameter family of solutions of the second-order DE y'' â y = 0. Find a solution of

SCORPION-xisa [38]

Answer:

$y(t) = 2e^t -e^{-t}$

Step-by-step explanation:

Assuming this complete problem: "In this problem,

y = c1ex + c2e−x

is a two-parameter family of solutions of the second-order DE

y'' − y = 0.

Find a solution of the second-order IVP consisting of this differential equation and the given initial conditions.

y(0) = 1, y'(0)= 3"

Solution to the problem

For this case we have a homogenous, linear differential equation with order 2, and with the general form:

$ay'' +by' +cy=0$

Where $a =1, b=0, c=-1$

And we can rewrite the differential equation in terms $y = e^{rt}$ like this:

$[e^{rt}]'' -e^{rt}=0$

And applying the second derivate we got:

$r^2 e^{rt} -e^{rt}=0$

We can take common factor $e^{rt}$ and we got:

$e^{rt} (r^2-1) =0$

And for this case the two only possibel solutions are $r=1, r=-1$

And the general solution for this case is given by:

$y = c_1 e^{r_1 t} + c_2 e^{r_2 t}$

Replacing the roots that we found we got:

$y = c_1 e^{t} +c_2 e^{-t}$

Now we can find the derivates for this last espression

$y' = c_1 e^t -c_2 e^{-t}$

$y'' = c_1 e^t +c_2 e^{-t}$

From the initial conditions we have this:

$y(0)=1 =c_1 e^{0} +c_2 e^{-0}= c_1 +c_2$ (1)

$y'(0) =3= c_1 e^{0} -c_2e^{-0}= c_1 -c_2$ (2)

If we add equations (1) and (2) we got:

$4 = 2c_1 , c_1 = 2$

And solving for $c_2$ we got:

$c_2=3-c_1= 3-2 = 1$

So then our general solution is given by:

$y(t) = 2e^t -e^{-t}$

8 0

3 years ago