3 years ago

Someone pls help me I need this to get math grade up

Mathematics

1 answer:

nexus9112 [7]3 years ago

8 0

9514 1404 393

Answer:

see attached

Step-by-step explanation:

Dilation by a factor of 3 about point P moves A to a position that is 3 times as far from P. This is shown in the attachment.

Dilation is always along a line through the original point and the center of dilation.

(The lines are there in the attachment simply to show you that the image position is 3 times the distance from P that the original position is. They are not part of the dilation or the image.)

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Find the distance UV between the points U(4,−2) and V(6,−1). Round your answer to the nearest tenth, if necessary.

Liono4ka [1.6K]

The horizontal distance is the difference of x-coordinates: 6 - 4 = 2.

The vertical distance is the difference of y-coordinates: -1 - (-2) = 1.

The straight-line distance (d) can be found using the Pythagorean theorem, since the vertical and horizontal distances are at right angles to each other.

.. d² = 2² + 1² = 5

.. d = √5 ≈ 2.2

The distance UV is about 2.2.

8 0

3 years ago

Given A is between Y and Z YA = 5.5, AZ = 2x, and YZ = 41.5 =, find AZ

morpeh [17]

YZ = YA + AZ
41.5 = 5.5 + AZ
AZ = 41.5 - 5.5
AZ = 36

So, your final answer is AZ = 36

Hope this helps!

4 0

3 years ago

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