If the vectors are 4i-6j and -i-5j then the angle between both the vectors is approximately 45°.
Given two vectors be 4i-6j and -i-5j.
We are required to find the angle between vectors 4i-6j and -i-5j.
A vector is basically an equation involving a linear combination of vctors with possibly unkown coefficients. Vector is basically a quantity that has both magnitude and direction but not possition.
Angle is basically measure of inclination of something with the surface.
The angles between two vectors can be find out by the following formula:
cos Θ=[dot product of both the vectors/(product of magnitude of both the vectors)
cos Θ=[4*(-1)+(-6)*(-5)]/
cos Θ=(-4+30)/
cos Θ=26/
cos Θ=26/26.77
cos Θ=0.7070
Θ=
(0.707)
Θ=45.008
Approximately 45°.
Hence if the vectors are 4i-6j and -i-5j then the angle between both the vectors is approximately 45°.
Learn more about vectors at brainly.com/question/25705666
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Answer:
(12) (x^4) (2)
Hope it helps.
Step-by-step explanation:
(3x^2 + 3) (4x^2 - 1)
(3 x 4) (x^2 X x^2) (3 - 1)
(12) (x^4) (2)
the answer is rounded to 0.2 miles but the answer is 0.15 because you divide the number 9 by minutes in an hour and you get 0.15 (rounded up to 0.2)
D 5/4 x - 4
You find the slope using the slope formula, 1-(-4)/4-0 which should give you 5/4 and then you substitute 5/4 into the equation y=mx+c . y=5/4x+ c. You take the x and y values of any of the two points and substitute them into this equation to solve for c which should give you -4.The equation of the line is 5/4x -4.Hope this helps!
Whenever you divide by 0.5 just double the number for the answer. Double 20 is 40. 40 is the answer.