What is the range of the function y=2x+1 for the domain 2<=x<=5?

1 answer:

5 0

So domain is the number you can use
range is the output your get from inputting the domain given
so from 2≤x≤5
since it is linear, we can be sure that we only need to test the endpoints of the domain to find the endpoints of the range

sub 2 for x
y=2(2)+1
y=4+1
y=5

sub 5 for x
y=2(5)+1
y=10+1
y=11

so range is from 5 to 11
in interval notation: [5,11]
in other notation 5≤y≤11
or
R={y|5≤y≤11}

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The function f(x) = One-sixth (two-fifths) Superscript x is reflected across the y-axis to create the function g(x). Which order

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The ordered pair (-3 , $\frac{4}{375}$ ) is on g(x) ⇒ 1st answer

Step-by-step explanation:

Let us revise the reflection across the axes

If the function f(x) reflected across the x-axis, then its image is g(x) = - f(x) (change the sign of y)
If the function f(x) reflected across the y-axis, then its image is g(x) = f(-x) (change the sign of x)

∵ $f(x)=\frac{1}{6}(\frac{2}{5})^{x}$

∵ f(x) is reflected across the y-axis to create the function g(x)

- Change the sign of x

∴ $g(x)=\frac{1}{6}(\frac{2}{5})^{-x}$

To find the point that lies on g(x) substitute x in g(x) by the x-coordinate of the point if the answer equal to the y-coordinate of the point, then the point lies on it if not then the point does not lie on it

∵ The coordinates of the point are (-3 , $\frac{4}{375}$ )

∴ x = -3 and y = $\frac{4}{375}$

- Substitute x by -3 in g(x)

∵ $g(x)=\frac{1}{6}(\frac{2}{5})^{-x}$

∴ $g(x)=\frac{1}{6}(\frac{2}{5})^{-(-3)}$