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3 years ago

Divide 24 into the ratio of 1:3?

Mathematics

2 answers:

Over [174]3 years ago

4 0

Answer:

6:18

Step-by-step explanation:

24=4

?=1

1*24/4=6

24-6=18

Phoenix [80]3 years ago

3 0

Answer: divide 24 by 3 basically

Answer is 8

Step-by-step explanation:

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Sergio is working on a research project involving the ages of students at Brooklyn College. After interviewing 500 students, he

Zinaida [17]

Answer:

The probability of of a randomly chosen student being exactly 21 years old.

= 1.293

Step-by-step explanation:

Step(i):-

Given Population size n = 500

Mean of the Population = 20 years and 6 months

= $20 + \frac{6}{12} = 20 +0.5 = 20.5 years$

Standard deviation of the Population = 2 years

Let 'X' be the range of ages of the students on campus follows a normal distribution

Let x =21

$Z = \frac{x-mean}{S.D}$

$Z = \frac{x-mean}{S.D} = \frac{21-20.6}{2} =0.2$

The probability of a randomly chosen student being exactly 21 years old.

P( Z≤21) = 0.5 + A( 0.2)

= 0.5 +0.793

= 1.293

6 0

3 years ago

In a survey, the planning value for the population proportion is . How large a sample should be taken to provide a confidence in

tatuchka [14]

Answer:

n=350

Step-by-step explanation:

Notation and definitions

$n$ random sample taken (variable of interest)

$\hat p=0.35$ estimated proportion (value assumed)

$p$ true population proportion

Confidence =0.95 or 95% (value assumed)

Me=0.05 (value assumed)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: