<h3>Given</h3>
Two positive numbers x and y such that xy = 192
<h3>Find</h3>
The values that minimize x + 3y
<h3>Solution</h3>
y = 192/x . . . . . solve for y
f(x) = x + 3y
f(x) = x + 3(192/x) . . . . . the function we want to minimize
We can find the x that minimizes of f(x) by setting the derivative of f(x) to zero.
... f'(x) = 1 - 576/x² = 0
... 576 = x² . . . . . . . . . . . . multiply by x², add 576
... √576 = x = 24 . . . . . . . take the square root
... y = 192/24 = 8 . . . . . . . find the value of y using the above equation for y
The first number is 24.
The second number is 8.
Wjdhiqhdydhhwjebfksomern
Enchiladas
Answer:
b because the value are correct
Step-by-step explanation:
Answer:
<u>The negative solution is -4</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
x = a number
4x = x² - 32 (4 times a number is 32 less than the square of that number)
2. Let's solve for x and find the negative solution:
4x = x² - 32
-x² + 4x + 32 = 0
x² - 4x - 32 = 0 (Multiplying by - 1)
(x - 8) (x + 4) = 0
(x₁ - 8) = 0
(x₂ + 4) = 0
x₁ = 8
<u>x₂ = -4</u>
<u>The negative solution is -4</u>
Can’t help you with this, we need either the picture of the graph or the formula for the graph
