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Mrac [35]
2 years ago
10

Expand and combine like terms. (4b^2+ 3) (4b^2- 3) = 1 SEE ANSWER

Mathematics
1 answer:
krok68 [10]2 years ago
8 0

Answer:

Step-by-step explanation:

(4b^2+3)(4b^2-3)

since it is the expanded form of formula a^2-b^2=(a+b)(a-b) we can write,

=(4b^2)^2-(3)^3

=16b^4-9

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Read 2 more answers
Find the standard deviation of 21, 31, 26, 24, 28, 26
Vesnalui [34]

Given the dataset

x = \{21,\ 31,\ 26,\ 24,\ 28,\ 26\}

We start by computing the average:

\overline{x} = \dfrac{21+31+26+24+28+26}{6}=\dfrac{156}{6}=26

We compute the difference bewteen each element and the average:

x-\overline{x} = \{-6,\ 5,\ 0,\ -2,\ 2,\ 0\}

We square those differences:

(x-\overline{x})^2 = \{36,\ 25,\ 0,\ 4,\ 4,\ 0\}

And take the average of those squared differences: we sum them

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And we divide by the number of elements:

\displaystyle \sigma^2=\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n} = \dfrac{69}{6} = 11.5

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8 0
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