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3 years ago

Which choice is equivalent to the expression below? 2sqrt(7) + 8sqrt(7)

Mathematics

1 answer:

dexar [7]3 years ago

5 0

Answer:

Dear Twinkie

Answer to your query is provided below

10√7 is the expression equivalent for 2√7+8√7.

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Which of the following is the solution set for -3t + 11 > 20?

Lelechka [254]

Answer: C. t < -3

<em>Hope this helps!</em>

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3 years ago

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Which is a solution to 2x + 1 = 21?

Bezzdna [24]

Answer:

x = 10 is your answer

- Explain -

Step 1: subtract 1 from both sides (subtraction of equality)

which will give us:

2x = 21 - 1

which equals to

2x = 20

Step 2: Divide both sides by 2

which is

2x/2 = 20/2

2/2 = 1 and 20/2 = 10

Therefore the answer is x = 10

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2 years ago

Addison worked 11 more hours this week than last week. In total, she worked 65 hours this week and last week. Using the equation

Anestetic [448]

Answer:

27 hours

Step-by-step explanation:

Just do the reverse. 65-11 = 54. 54 / 2 = 27.

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2 years ago

Convert .06 yards to inches. A) 2.16 inches B) 2.88 inches C) 21.6 inches D) 28.8 inches

sweet-ann [11.9K]

A yard is 36 in so multiply.06 by 36
The answer is a.2.16 inches

7 0

3 years ago

Read 2 more answers

K is the midpoint of PQ, P has

Pachacha [2.7K]

Answer:

Coordinates of Q $(x_2,y_2) \:are\: \mathbf{(7,16)}$

Option D is correct option.

Step-by-step explanation:

We are given:

K is the midpoint of PQ

Coordinates of P = (-9,-4)

Coordinates of K = (-1,6)

We need to find coordinates of Q $(x_2,y_2)$

We will use the formula of midpoint: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

We are given midpoint K and $x_1,y_1$ the coordinates of P we need to find $x_2,y_2$ the coordinates of Q.

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\$

Now, we can write

$-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16$

So, we get coordinates of Q $(x_2,y_2) \:are\: \mathbf{(7,16)}$

Option D is correct option.

6 0

2 years ago