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Lena [83]
3 years ago
10

A fast food restaurant processes on average 5000 pounds of hamburger per week. The observed inventory level of raw meat, over a

long period of time, averages 2500 pounds. What is the average time spent by a pound of meat in production (in weeks)
Mathematics
1 answer:
elixir [45]3 years ago
6 0

Answer:

0.5 week

Step-by-step explanation:

The time spent by a pound of meat in this system is given by the average number of pounds of meat on inventory (2500 pounds) divided by the average weekly meat consumption (5000 pounds per week).

The time, in weeks, is:

t=\frac{2500\ pounds}{5000\ pounds/week} \\t= 0.5\ week

The average time spent by a pound of meat in production is 0.5 week.

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disa [49]
The answer is 7.9306

Using the formula in the attached:
Where: xi = sample value; μ = sample mean; n = sample size

1.) Calculate the mean first:
μ = 12.0 + 18.3 + 29.6 + 14.3 + 27.8 / 5
   = 102 / 5
μ = 20.4

2.) Using the mean, calculate (xi - μ)² for each value:
(12.0 - 20.4)² = 70.56
(18.3 - 20.4)² = 4.41
(29.6 - 20.4)² = 84.64
(14.3 - 20.4)² = 37.21
(27.8 - 20.4)² = 54.76

3.) Sum the squared differences and divide by n - 1.
μ = 70.56 + 4.41 + 84.64 + 37.21 + 54.76
   = 251.58 / 5-1
μ = 62.895 (this is now called sample variance)

4.) Get the square root of the sample variance:
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3 years ago
What is solution to 3/5=z/10
zhannawk [14.2K]
Z=6

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The table would be y = 6x

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Hey there! I'm happy to help!

To find the x value of the midpoint, you add the x values and divide by 2.

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