The slope is -4. This is because of slope intercept form, y=mxtb. M= the slope so the slope in this case is -4
The solution to the equation is p = 1/3 and q = undefined
<h3>How to solve the equation?</h3>
The equation is given as:
p^2 - 2qp + 1/q = (p - 1/3)
The best way to solve the above equation is by the use of a graphing calculator i.e. graphically
However, it can be solved algebraically too (to some extent)
Recall that the equation is given as:
p^2 - 2qp + 1/q = (p - 1/3)
Split the equation
So, we have
p^2 - 2qp + 1/q = 0
p - 1/3 = 0
Solve for p in p - 1/3 = 0
p = 1/3
Substitute p = 1/3 in p^2 - 2qp + 1/q = 0
So, we have
(1/3)^2 - 2q(1/3) + 1/q = 0
This gives
1/9 - 2/3q + 1/q = 0
This gives
2/3q + 1/q = -1/9
Multiply though by q
So, we have
2/3q^2 + 1 = -1/9q
Multiply through by 9
6q^2 + 9 = -q
So, we have
6q^2 + q + 9 = 0
Using the graphing calculator, we have
q = undefined
Hence. the solution to the equation is p = 1/3 and q = undefined
Read more about equations at:
brainly.com/question/13763238
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X=-56/3
multiply everything by 4 to cancel the fraction which will give you
3x+20=-36
then combine like terms to get
3x=-56
then divide to get x by itself to get
x=-56/3
since this is a weird decimal, leave it as an improper fraction
An exponential function can be expressed as:
y=ab^x we have two points so we can solve
64/8=(ab^4)/(ab^1)
8=b^3
2=b, now we have:
y=a(2^x), using point (4,64)
64=a(2^4)
64=16a
4=a so
y=4(2^x)
