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iris [78.8K]
3 years ago
13

In attempting to calculate the carrying capacity of a cylindrical pipe, Avery measured the outer diameter to be 2 inches, neglec

ting to notice that the pipe was one eighth of an inch thick. By what percent did Avery overestimate the carrying capacity of the pipe?
Mathematics
1 answer:
andreev551 [17]3 years ago
4 0
Volume of the pipe = πr^2l
Wrong measure = π x (2)^2 x l = 4πl
Correct measure = π x (2 - 2(1/8))^2 x l = 49/16πl
error = 4πl - 49/16πl = 15/16πl

% error = ((15/16πl) / 49/16πl) x 100% = 30.6%
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Y+x=1 show whether x and y show direct variation ​<br><br><br>plzz helpp
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Answer:

No

Step-by-step explanation:

Please write:  "Determine whether y+x=1 shows direct variation."

No, it does not, because of the constant term, 1.

If we were to eliminate the 1 and write y + x = 0, then yes, this would represent direct variation.

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3 years ago
Vugar has a maximum of 30 batteries for toys. Each toy helicopter uses the same number of batteries, and each toy car uses the s
Leno4ka [110]

Answer: 3H+4C<_ 30

The coefficients of the variables H and C represent the number of batteries each toy helicopter and each toy car uses.

Step-by-step explanation:

Each toy helicopter uses 3 batteries, and each toy car uses 4 batteries.

Now let's check whether Vugar has enough batteries for 5 toy helicopters and 4 toy cars. To do this, we substitute  H=5 and C= 4 in the given inequality:

Does Vugar have enough batteries to play with 5 toy helicopters and 4 toy cars?

No, because if you plug in the value for H and C:

3H + 4C<_ 30

3(5) + 4(4) <_30

15 + 16 <_ 30

31 <_ 30; false

Since the inequality is false, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.

Each toy helicopter uses 333 batteries, and each toy car uses 444 batteries.

No, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.

6 0
3 years ago
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Joe cannons charges an initial fee of $20 +4 dollars an hour Calais Calais charges a flat rate of $14 an hour find the number of
lara [203]

Answer:

Step-by-step explanation:

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3 years ago
HELP ASAP IM STUPIDDDDD <br><br><br> Write the power as a product of factors: 9^7
algol [13]

Answer:

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Lia must work at least 5 hours per week in her family’s restaurant for $8 per hour. She also does yard work for $12 per hour. Li
Fittoniya [83]

Answer:

(a)

r\geq  5

r+y\leq 15

8r+12y\geq 120

y\geq 0

(c)Maximum number of hours Lia can work at the restaurant and still meet her earnings goal = 15 hours

(d)Maximum Earning = $160

Step-by-step explanation:

Let r be the number of hours worked at the restaurant.

Let y be the number of hours of yard work,

Lia must work at least 5 hours per week in her family’s restaurant for $8 per hour.

r\geq  5

Since she does yard work, y\geq 0

Lia’s parents allow her to work a maximum of 15 hours per week overall.

r+y\leq 15

Lia’s goal is to earn at least $120 per week.

The restaurant, r pays $8 per hour

Yard work, y pays $12 per hour.

Therefore:

8r+12y\geq 120

The system of inequalities that represent this problem is therefore:

r\geq  5

r+y\leq 15

8r+12y\geq 120

y\geq 0

(b)The graph of the inequality is attached below

(c)When the graph is plotted, the vertices of the feasible region are:

  • (5,10)
  • (5, 6.7)
  • (15,0)

Where the first term is for the number of hours worked in the restaurant.

The maximum value of r possible is 15 from the three points.

Therefore, she can work at the restaurant for 15 hours and still meet her earning goal.

(d)Maximum Amount Lia can earn in 1 Week

  • At (5,10), Earning=(5X8)+(10X12)=40+120=$160
  • At (5, 6.7), Earning=(5X8)+(6.7X12)=40+80.4=$120.4
  • At (15,0) Earning=(15X8)+(0X12)=$120

Since she has to work at least 5 hours at the restaurant, the maximum amount possible is $160.

8 0
3 years ago
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