The square root of negative four is 2
<span>The equation is not quadratic in for because it cannot be written as a second degree polynomial</span>
Step-by-step explanation:
u.v=|u||v|cos60°
u.v=(2.5)(3.2)(1/2)
u.v=(8)(1/2)
u.v=4
Answer:
The answer is undefined.
Step-by-step explanation:
Slope is found using this equation: y-y1/x-x1. Fill in the coordinates to this equation. It should now look like this. -7--3/-5--5. When subtracting from two negatives, it changes into a positive. For example, -7--3 becomes -7+3, which equals -4. The same thing applies for the second part. -5--5 becomes -5+5, which equals 0. So, your slope is -4/0. However, when a 0 is in the denominator, it becomes undefined. So, the answer is undefined.
Hello, when x tends to 
the term with the highest degree will lead the behaviour.
In other words.
So, the answer B is correct.
Thank you.
