<h2>D. 50 units</h2>
Hi, I’m Lena and I will be answering your question to the best of my ability. If you have any further questions after my answer, do not hesitate to ask me! ツ
♡ Let’s look at the main important thing(s) that will lead you in the correct path.
♥ The perimeter is the outside, it is <em>around</em> the figure. When you see those inner triangles, do not pay attention to them! They are just there to make your overthink the question.
♡ Let's solve!
♥ To begin, let's take LM. It already gives you half the segment, so all you need to do is double the number. 9*2=18.
♥ Now, let's take a look at NR. They already give you the segment as a whole, so you do not need to worry about it!
♥ Look at SR. You do the same thing as you did to LM, double the number. 8*2=16.
Now, we add all the numbers to get our final answer.
18+16+16=50.
Sin60 =b/10
<span>√3/2 = b/10
</span>b = <span>√3 / 2 (10)
</span>b = 5<span>√3
</span>
d^2 = 10^2 - (5√3)^2
d^2 = 100 - 75
d^2 = 25
d = 5
sin30 = b/a
1/2 = 5√3 / a
a = 5√3 (2)
a = 10√3
c^2 = (10√3)^2 - (5√3)^2
c^2 = 300 - 75
c^2 = 225
c = 15
so
a =10√3, b = 5√3, c = 15,d = 5
answer is
D. last choice
Sam divided a rectangle into 8 congruent rectangles that each have a area of 5 cm2. what is the area of the rectangle before it is divided?
Answer:
Step-by-step explanation:
Given:
Sam divided a rectangle into 8 congruent rectangles that each have an area of 
We need to find the area of the rectangle before Sam divided it.
The area of the rectangle before Sam divided is 8 times of the area of the congruent rectangles.
Area of the rectangle =
Area of the congruent rectangle is 
So the area of the rectangle is
Area of the rectangle =
Area of the rectangle =
Therefore the area of the rectangle before divided is
To factor you have to do this:
s^2 + 9s = -20
+ 20 +20
s^2 + 9s + 20 = 0
now you need to numbers that multiplied give you 20
and then those same 2 numbers have to add to 9
5 x 4 = 20
5+ 4 = 9
(x + 4) (x+ 5)
that means that x= -4, and -5
Answer:
i dont know sry
Step-by-step explanation: