<span>Hard disk drives
</span><span>RAM<span>Random access memory (RAM)
</span></span><span>External hard disks
<span>USB port
</span></span>CD and DVD drives
<span>Memory cards</span>
Answer:
The output is: Your cost is 100
Explanation:
Given
The above code snippet
and
Required
Determine the output of the code
if cost < 70 or cost > 150
The above condition checks if cost is less than 70 or cost is greater than 150
This condition is false because 100 is neither less than 70 nor is it greater than 150
So, the else statement will be executed.
discount = cost
Which means
discount = 100
So, the print instruction will print: Your cost is 100
We can define a word as a group of characters without a space between them. To find the words of the input string , w can use split(delimiter) which returns a list of strings which had the defined delimiter between them in the input string.
def countWords(string):
words = string.split(" ")
count = len(words)
return count
Here we set the delimiter as the space character, and returned the length of the words list. I split each step into its own line for readability, however the function could be one line:
return len(string.split())
Here, no delimiter is specified. If one isn't given, it will default to split at any whitespace, including space.
Was this in reference to literal audio archives? If so, I don't see any cons beside possible copyright infringement.
If you're talking about the codecs themselves, then I can do that.
<span>Pros:
</span>- Widespread acceptance. Supported in nearly all hardware devices, and continually adopted by newer ones.
- Faster decoding. Much more so than FLAC, Vorbis, etc.
- Relaxed licensing schedule.
<span>Cons:
</span><span>
</span>- Lower quality and efficiency than most modern codecs. (To be fair, never really noticed this one).
- Sometimes the maximum bitrate isn't enough.
- Pretty much void/unusable for high definition audio (higher than <span>48kHz).</span>
