Answer:
10 bits
Explanation:
Cache size = 32 KB
We were also given that it is 2 way set associative
Block size = 16 bytes = 2^4 = 4 bits for offset
Number of blocks = cache size / block size = (32*2^10) / 16
=2^11
Hence, index = number of blocks / 2 (since 2 way associative)
=(2^11)/2 = 2^10 = 10 bits for index
Answer:
Functional Family Therapy
Explanation:
According to my research on different types of therapies, I can say that based on the information provided within the question the therapy being described in this scenario is called Functional Family Therapy. This is a type of therapy aimed at young teens roughly aged 11-18 who are exhibiting violent or negative behaviors and/or substance abuse. The therapist sits down with the child, their parents, and sometimes an officer of the law in order to get to the root of the problem and come up with different solutions that may help the child feel less angry and prone to act out.
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It uses a special 'language' or code to tell it what to do a what times, why, and how. It gives the Computer an 'easier' Operating System (OS) to run on / off of. The OS makes The Computer easier for us, to use and understand.
Answer:
spanning-tree portfast bpduguard
Explanation:
spanning- tree protocol (STP) is a layer 2 protocol in the OSI model. It is automatically configured in a switch to prevent continual looping of BPDUs, to avoid traffic congestion. The fastport bpduguard is only applicable in non-trunking access in a switch. It is more secure to configure the fastport mode in switch port connected directly to a node, because there are still bpdus transfer in a switch to switch connection.
BPDUs Guard ensures that inferior bpdus are blocked, allowing STP to shut an access port in this regard.
