Answer:
Part A) ![sin(A)=\frac{2\sqrt{42}}{23}](https://tex.z-dn.net/?f=sin%28A%29%3D%5Cfrac%7B2%5Csqrt%7B42%7D%7D%7B23%7D)
Part B) ![cos(A)=\frac{19}{23}](https://tex.z-dn.net/?f=cos%28A%29%3D%5Cfrac%7B19%7D%7B23%7D)
Part C) ![tan(A)=\frac{2\sqrt{42}}{19}](https://tex.z-dn.net/?f=tan%28A%29%3D%5Cfrac%7B2%5Csqrt%7B42%7D%7D%7B19%7D)
Step-by-step explanation:
Part A) we know that
In the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuse
so
![sin(A)=\frac{BC}{AB}](https://tex.z-dn.net/?f=sin%28A%29%3D%5Cfrac%7BBC%7D%7BAB%7D)
substitute the values
![sin(A)=\frac{2\sqrt{42}}{23}](https://tex.z-dn.net/?f=sin%28A%29%3D%5Cfrac%7B2%5Csqrt%7B42%7D%7D%7B23%7D)
Part B) we know that
In the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse
so
![cos(A)=\frac{AC}{AB}](https://tex.z-dn.net/?f=cos%28A%29%3D%5Cfrac%7BAC%7D%7BAB%7D)
substitute the values
![cos(A)=\frac{19}{23}](https://tex.z-dn.net/?f=cos%28A%29%3D%5Cfrac%7B19%7D%7B23%7D)
Part C) we know that
In the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle A
so
![tan(A)=\frac{BC}{AC}](https://tex.z-dn.net/?f=tan%28A%29%3D%5Cfrac%7BBC%7D%7BAC%7D)
substitute the values
![tan(A)=\frac{2\sqrt{42}}{19}](https://tex.z-dn.net/?f=tan%28A%29%3D%5Cfrac%7B2%5Csqrt%7B42%7D%7D%7B19%7D)
Answer:
3/9 because theyre both equivalent to 1/3
Well, the keyword here is One of the performers insist on being the last.
So, the amount of performers that we can arrange freely is 7 performers.
Different ways we can schedule their appearance is :
7 ! = 7 x 6 x 5 x 4 x 3 x 2 x 1
= 5040
hope this helps
The Answer For Number Two Is Negative 14
You just have to plug in each thing:
So f(0):
3(0)^2 - 4 = -4
so its not A
f(-2) and f(2):
3(-2)^2 - 4
3(2)^2 -4
now we don't even have to calculate these, anything to the power of an even number is a positive number so -2^2 and 2^2 both equal 4
B is correct, so you can do the others if you want to check, but if B is true the others shouldn't be true.