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dexar [7]
3 years ago
8

What is the value of (3 x 10-2)​

Mathematics
1 answer:
Andru [333]3 years ago
4 0

Answer:

28

Step-by-step explanation:

first Multiply 3*10

where you wil get 30

then,

subtract 2 from 30

where as :

30-2 =28

Fianl answer is 28

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Help 50 point for helping me
baherus [9]
The answer would be B because you know she has two purses that are $12 each however you don’t know how many scarves she has so you need 5n+12 to get to 38
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The area of a rectangle is x2 - 2x - 15 and the length of the rectangle is x + 3. Find the width of the rectangle.
Alexandra [31]
The area of the triangle could be determined by multiplying the length and the width. Since, we are given the area and the length, to find the width, you divide the area by the length:

w = A ÷ l
w = (x2 - 2x - 15) ÷ (x+3)

What do you have to multiply to (x+3) to yield x2 - 2x - 15? That would be x - 5. Since the sum of -5 and 3 = -2 (middle term) and the their product is -15 (last term).

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Which list gives all of the line segments in the figure
aalyn [17]

Answer:

A. AB, BC, CD, AD, AC, BD

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Gre4nikov [31]

Answer: point form (-1,-2)

Equation form x=-1 y=-2

Step-by-step explanation:

7 0
3 years ago
Components of a certain type are shipped to a supplier in batches of ten. Suppose that 50% of all such batches contain no defect
ad-work [718]

Answer:

a) P (0 defective component) = 0.5

   P( 1 defective component ) = 0.35

    P( 2 defective component ) = 0.15

b) P( 0 ) = 0

   p ( 1 ) =  1

   p ( 2 ) = 0.33

Step-by-step explanation:

p( no defective ) = 0.5

p( 1 is defective ) = 0.35

p( 2 is defective ) = 0.15

Given that 2 components are selected at random

<u>a) Given that neither component is defective </u>

Probability of 0 defective component = 0.5

P( 1 defective component ) = 0.35

P( 2 defective component ) = 0.15

<u>b) Given that one of the two tested component is defective </u>

P( 0 defective ) = 0

P( 1 defective ) = P ( \frac{x=1}{x\geq 1} ) = p( x = 1 ) / 1 - P ( x = 0 )

                                        = ( 0.5 )^1 ( 0.5 )^0 /  1 - ( 0.5)^0 (0.5)^1

                                        = 0.5 * 1 / 1 - 0.5 = 0.5 / 0.5 =  1

p ( 2 defective ) = p( x = 3 ) / 1 - P ( x = 0 )

                         = ( 0.5 )^2 ( 0.5 )^0 /  1 - ( 0.5)^0 (0.5)^2

                         = 0.25 / 0.75 = 0.33

<u />

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2 years ago
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